All categories

3 years ago

What is the magnitude of the gravitational force acting on the earth due to the sun?

Physics

2 answers:

expeople1 [14]3 years ago

3 0

Answer: $3.524(10)^{22}N$

Explanation:

According to Newton's law of Gravitation, the force $F$ exerted between two bodies of masses $m1$ and $m2$ and separated by a distance $r$ is equal to the product of their masses and inversely proportional to the square of the distance:

$F=G\frac{(m1)(m2)}{r^2}$ (1)

Where:

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$m1=1.99(10)^{30}kg$ is the mass of the Sun

$m2=5.972(10)^{24}kg$ is the mass of the Earth

$r=1.50(10)^{11}m$ is the distance between the Sun and the Earth

Substituting the values in (1):

$F=6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}\frac{(1.99(10)^{30}kg)(5.972(10)^{24}kg)}{(1.50(10)^{11}m)^2}$ (2)

Finally:

$F=3.524(10)^{22}N$ This is the gravitational force acting on the earth due to the sun

drek231 [11]3 years ago

3 0

The magnitude of the gravitational force : <u>3.48.10²² N</u>

<h3>Further explanation </h3>

Gravity is a force that arises because of the attraction between objects with mass.

The magnitude of this attraction is proportional to the mass of the object.

The greater the mass of the object, the greater the gravitational force

Relationships can both be stated in

Newton's Gravity Law:

$\rm F=G.\dfrac{m_1.m_2}{r^2}$

with F = gravitational force,

G = gravitational constant,

m1, m2 = mass of object,

r = distance between two objects.

From the available data:

m earth = 5.98.10²⁴ kg

m sun = 1.99.10³⁰ kg

r = 150 million km = 15.10⁷ km = 15.10¹⁰ m

G = 6.67.10⁻¹¹N.m² / kg²

We put in the formula:

$\rm F=6.67.10^{-11}.\dfrac{5.98.10^{24}.1.99.10^{30}}{(15.10^{10})^2}\\\\F=3.48.10^{22}\:N$

So <em>The earth exerts 3.48.10²² N of force on the sun, exactly the same amount of force the sun exerts on the earth</em>

<h3>Learn more </h3>

Isaac Newton's investigations of gravity

brainly.com/question/1747622

Gravitational force

brainly.com/question/7955425

increase the gravitational force between two objects

brainly.com/question/2306824

Keywords: gravitational force, Newton's Gravity Law, mass, sun,earth

You might be interested in

1. The picture below shows Jamal pushing with a 100-Newton (N) force on a large box. Neither

r-ruslan [8.4K]

Answer:

100 newtons

Explanation:

Given,

Jamal pushing a large box by a force, F = 100 N

Work done on the large box is, W = 0

It is because the applied force is less than the force of the friction between the two surfaces.

Yet, there will be a force that is exerted by the large box on Jamal.

According to newton's third law of motion, every action has an equal and opposite reaction. The reaction force is in the direction opposite to the force of action. But, their magnitude remains the same.

$F_{a} =-F_{r}$

Hence, If the action force is 100 N, then the reaction force should be in 100 N

4 0

4 years ago

Read 2 more answers

State 2 chemical properties of metals

Ivahew [28]

Answer:

#they react with oxygen to form basic oxides.

#they react with water to produce hydrogen and oxides

#they react with acids to produce H+

3 0

2 years ago

Read 2 more answers

An electric ceiling fan is rotating about a fixed axis with an initial angular velocity magnitude of 0.200 rev/s . The magnitude

blagie [28]

Answer:

(A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

Explanation:

Given that,

Initial angular velocity = 0.200 rev/s

Angular acceleration = 0.883 rev/s²

Diameter = 0.760 m

Time = 0.204 s

(A). We need to calculate the angular velocity of fan

Using equation of angular motion

$\omega_{f}=\omega_{i}+\alpha t$

Put the value into the formula

$\omega_{f}=0.200+0.883\times0.204$

$\omega_{f}=0.380\ rev/s$

(B). We need to calculate the number of revolution

Using formula of angular displacement

$\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2$

Put the value into the formula

$\theta=0.200\times0.204+\dfrac{1}{2}\times0.883\times(0.204)^2$

$\theta=0.059\ rad$

(C). We need to calculate the tangential speed of the blade

Using formula of speed

$v=\dfrac{d}{2}\omega_{f}$

Put the value into the formula

$v=\dfrac{0.760}{2}\times0.380\times2\pi$

$v=0.907\ m/s$

(D). We need to calculate the tangential acceleration of the blade

Using formula of tangential acceleration

$a_{t}=\alpha r$

Put the value into the formula

$a_{t}=0.883\times0.38\times2\pi$

$a_{t}=2.10\ m/s^2$

Hence, (A). the angular velocity of fan is 0.380 rev/s.

(B). The number of revolution is 0.059 rad.

(C). The tangential speed of the blade is 0.907 m/s.

(D). The tangential acceleration of the blade is 2.10 m/s²

3 0

3 years ago

A vehicle start moving at 15m/s. How long will it take to stop at a distance of 15m?

Alekssandra [29.7K]

Answer:

Explanation:

Speed= distance/time

Or time = distance/speed

According to your question

Speed=15m/s

and. Distance=1.2km. ,we must change kilometer in meter because given speed is in m/s

D= 1.2km = 1.2×1000m =1200meter

Time = distance/ speed

1200/15 =80second

Or. 1min and 20 sec will be your answer.

3 0

2 years ago

A ball whose mass is 0.3 kg hits the floor with a speed of 7 m/s and rebounds upward with a speed of 4 m/s. if the ball was in c

Maurinko [17]

Newton's second law is stated as:
F=ma,

a = (7-4)/1.5 = 2 m/s^2 (it is a deceleration due to impact with floor. And thus the ball exerts force on the floor).

Therefore,

F= 0.3*2 = 0.6 N

8 0

3 years ago