The answer is 16, you substitute the value of the variable into the equation and simplify
since we have the area of the front side, to get its volume we can simple get the product of the area and the length, let's firstly change the mixed fractions to improper fractions.
![\stackrel{mixed}{23\frac{2}{3}}\implies \cfrac{23\cdot 3+2}{3}\implies \stackrel{improper}{\cfrac{71}{3}} ~\hfill \stackrel{mixed}{4\frac{7}{8}}\implies \cfrac{4\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{39}{8}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{71}{3}\cdot \cfrac{39}{8}\implies \cfrac{71}{8}\cdot \cfrac{39}{3}\implies \cfrac{71}{8}\cdot 13\implies \cfrac{923}{8}\implies 115\frac{3}{8}~in^3](https://tex.z-dn.net/?f=%5Cstackrel%7Bmixed%7D%7B23%5Cfrac%7B2%7D%7B3%7D%7D%5Cimplies%20%5Ccfrac%7B23%5Ccdot%203%2B2%7D%7B3%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B71%7D%7B3%7D%7D%20~%5Chfill%20%5Cstackrel%7Bmixed%7D%7B4%5Cfrac%7B7%7D%7B8%7D%7D%5Cimplies%20%5Ccfrac%7B4%5Ccdot%208%2B7%7D%7B8%7D%5Cimplies%20%5Cstackrel%7Bimproper%7D%7B%5Ccfrac%7B39%7D%7B8%7D%7D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Ccfrac%7B71%7D%7B3%7D%5Ccdot%20%5Ccfrac%7B39%7D%7B8%7D%5Cimplies%20%5Ccfrac%7B71%7D%7B8%7D%5Ccdot%20%5Ccfrac%7B39%7D%7B3%7D%5Cimplies%20%5Ccfrac%7B71%7D%7B8%7D%5Ccdot%2013%5Cimplies%20%5Ccfrac%7B923%7D%7B8%7D%5Cimplies%20115%5Cfrac%7B3%7D%7B8%7D~in%5E3)
Answer: the number of the parking space covered by the car is 87
Step-by-step explanation:
Numbers are assigned to each parking spot. Looking closely at the numbers assigned to each spot, the numbers are inverted and the number on each successive spot differ by one. The numbers are 86, 87, 88, 89, 90, 91
Therefore, the number assigned to the spot where the car would be 87
Answer:
9.
h(x)=-x-1
let y =-x-1
interchanging role of x & y
x=-y-1
y=-x-1
h-¹(x)=-x-1
again
f(x)=(2-3x)/2
let
y=(2-3x)/2
interchanging role of x & y
x=(2-3y)/2
2x-2=-3y
y=(2-2x)/3
f-¹(x)=(2-2x)/3
<u>G</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>f</u><u>u</u><u>n</u><u>c</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>a</u><u>r</u><u>e</u><u> </u><u>n</u><u>o</u><u>t</u><u> </u><u>i</u><u>n</u><u>v</u><u>e</u><u>r</u><u>s</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>c</u><u>h</u><u> </u><u>o</u><u>t</u><u>h</u><u>e</u><u>r</u><u>.</u>
10.
f(x)=-x+3
let y=-x+3
interchanging role of x & y
x=-y+3
y=3-x
f-¹(x)=-x+3
equal to g(x)=-x+3
<u>Given function are</u><u> inverse of each other.</u>
Answer:
Mutiply this by whatever other value there is.
Step-by-step explanation: