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3 years ago

x __ = 16

Mathematics

1 answer:

Arlecino [84]3 years ago

6 0

1) 4 times 4 = 16
2) 2 times 2 times 9 = 36
3) 4 times 2 times 9 = 72
4) x + y + z = n
(any solution that is true)

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If 2y = 6 - 3x, find y when x = 0

MakcuM [25]

Answer:

2y= 6-3x when x=0

2y= 6-3(0)

2y= 6-0

2y= 6

y= 6/2

y= 3

#i'm indonesian

#hope it helps.

8 0

3 years ago

Read 2 more answers

The perimeter it a square field is 224. How long is

geniusboy [140]

Since each side of a sqare is equal and there are four sides to the square
$224 = 4x$
X being the side length.
Then you would simiply divide by 4 to isolate x
$x = 56$
A side length is 56

8 0

3 years ago

Karen went to the farmers market

Zinaida [17]

Answer:

6 papayas and 11 pineapples

Step-by-step explanation:

So, we need to find an answer of how many papayas and pineapples she bought, and we only spent $48.

So, papayas are $2.50 each, and Pineapples are $3.00 each and we only bought 17 fruits total.

lets try 8 papayas, and 9 Pineapples.

$2.50 x 8 = $20.00 total on Papayas

$3.00 x 9 = $27.00 total on Pineapples.

That would only be $47 spent total.

Lets try 10 papayas and 7 pineapples.

$2.50 x 10 = $25.00

$3.00 x 7 = $21.00

That would only be a total of $26 spent.

Lets try 6 papayas and 11 pineapples.

$2.50 x 6 = $15.00

$3.00 x 11 = $33.00

This would be a total of $48 spent.

8 0

3 years ago

Factorise 15x-5 <br> factorise x^2-5x+6

kotegsom [21]

5(3x-1) (x-3)(x-2) I don't know if you want working out or an explanation? Or if it's too late, sorry.

5 0

2 years ago

A poll asked 1057 American adults if they believe there was a conspiracy in the assassination of President Kennedy, and found th

AVprozaik [17]

Answer:

The 95% confidence interval of the proportion of Americans who believe in the conspiracy is $0.551< p < 0.610$

Step-by-step explanation:

From the question we are told that

The sample size is n =1057

The number that believe there was a conspiracy is k = 614

Generally the sample proportion is mathematically represented as

$\^ p = \frac{614}{1057 }$

=> $\^ p = 0.5809$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{0.5809 (1- 0.5809)}{1057} }$

=> $E = 0.02975$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.5809 - 0.02975< p < 0.5809 + 0.02975$

=> $0.551< p < 0.610$

4 0

3 years ago

______ x ________ = 16

x __ = 16