Answer:
e
f
∘
g
(
x
)
=
2
x
2
−
4
x
−
3
And
g
∘
f
(
x
)
=
(
2
x
−
3
)
(
2
x
−
5
)
Step-by-step explanation: f
(
x
)
=
2
x
−
3
g
(
x
)
=
x
2
−
2
x
=
f
(
g
(
x
)
)
=
f
(
x
2
−
2
x
)
=
2
(
x
2
−
2
x
)
−
3
=
2
x
2
−
4
x
−
3
g
∘
f
(
x
)
=
g
(
f
(
x
)
)
=
g
(
2
x
−
3
)
=
(
2
x
−
3
)
2
−
2
(
2
x
−
3
)
=
(
2
x
−
3
)
(
2
x
−
3
−
2
)
=
(
2
x
−
3
)
(
2
x
−
5
)
f
∘
g
(
x
)
≠
g
∘
f
(
x
)
<h2><u>
PROPORTIONAL EQUATION</u></h2><h3>Exercise</h3>
Apply the means-extremes property of proportions: this allows you to cross multiply:
Apply the distributive property:
Add 24 to both sides:
Substract 3x to both sides
<h3><u>Answer</u>. The value of x = 24.</h3>
We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
6y+11=23
-11 -11
6y=12
/6 /6
y=2
5x-55
