Answer:
3 times
Explanation:
We know that:
small diameter = 2 * 10^-2 in
large diameter = 6 * 10^-2 in
We want to know how many times larger is the thin diameter compared to the large one.
We will do this as follows:
large diameter = k * small diameter
where k is the number of times that we want to find
6 * 10^-2 = k * 2 * 10^-2
k = (6 * 10^-2) / (2 * 10^-2)
k = 3
This means that the large diameter is 3 times the small one.
Hope this helps :)
Step-by-step explanation:
I don't know this math yet
sorry
Answer:
6
Step-by-step explanation:
10/5 ×/3 multiply 10×3 and than divide by 5
or another way start with multiplying 5 and n equaling 5n=
than 10× 3= 30 so you're left with 5n=30 divied 30 by 5 equalling 6
so x=6
108=2x-4(2x-9)
108=2x-8x+36
108=-6x+36
-36 -36
72=-6x
72/-6=-6x/-6
-12=x
This should be easy because we just have to use substitution method. Substitute the value of x from the second equation into the x of the first equation.
-4(2y) + 11y = 15
-8y + 11y = 15
3y = 15 ; y = 5
Substitute this value of y to either the first or second equation.
x = 2(5) = 10
The ordered pair is therefore (10,5).
