All categories

3 years ago

Which step shows the result of applying the subtraction property of equality?

Mathematics

1 answer:

Scilla [17]3 years ago

7 0

Answer:

First step

Step-by-step explanation:

Subtract the 4 to the other side making the equation

(12x+8)+4=3

12x+8=-1

12x=-9

x=-3/4

You might be interested in

The area of a rectangle is 40 square feet. What could be the perimeter of the rectangle? how is this problem solved.

schepotkina [342]

A possible perimeter for the rectangle would be 28

Area=L x W

40/10=4

Width=4, Length=10

Perimeter=L+L+W+W

4+4+10+10=28

4 0

3 years ago

Read 2 more answers

Which word completely describes the rhombus?<br> A.equilateral<br> B.equiangular<br> C.regular

lara [203]

I say A. because all the sides are the same.

5 0

3 years ago

Read 2 more answers

90+y+6x+6x/2=360 What does x and y eqaul

Cerrena [4.2K]

Answer:

go to mathhhhh way . Com

Step-by-step explanation:

8 0

2 years ago

Explicit rule for sequence 5, 3, 1, -1, -3...

Phantasy [73]

Answer: 2

Step-by-step explanation: subtract by 2 every time.

4 0

3 years ago

The Ace Novelty company produces two souvenirs: Type A and Type B. The number of Type A souvenirs, x, and the number of Type B s

Molodets [167]

Answer:

500 type A; 3500 type B

Step-by-step explanation:

The method of Lagrange multipliers can solve this quickly. For objective function f(x, y) and constraint function g(x, y)=0 we can set the partial derivatives of the Lagrangian to zero to find the values of the variables at the extreme of interest.

These functions are ...

$f(x,y)=4x+2y\\g(x,y)=2x^2+y-4$

The Lagrangian is ...

$\mathcal{L}(x,y,\lambda)=f(x,y)+\lambda g(x,y)\\\\\text{and the partial derivatives are ...}\\\\\dfrac{\partial \mathcal{L}}{\partial x}=\dfrac{\partial f}{\partial x}+\lambda\dfrac{\partial g}{\partial x}=4+\lambda (4x)=0\ \implies\ x=\dfrac{-1}{\lambda}\\\\\dfrac{\partial \mathcal{L}}{\partial y}=\dfrac{\partial f}{\partial y}+\lambda\dfrac{\partial g}{\partial y}=2+\lambda (1)=0\ \implies\ \lambda=-2$

$\dfrac{\partial\mathcal{L}}{\partial\lambda}=\dfrac{\partial f}{\partial\lambda}+\lambda\dfrac{\partial g}{\partial\lambda}=0+2x^2+y-4=0\ \implies\ y=4-2x^2\\\\\text{We know $\lambda$, so we can find x and y:}\\\\x=\dfrac{-1}{-2}=0.5\\\\y=4-2\cdot 0.5^2=3.5$

Since x and y are in thousands, maximum profit is to be had when the company produces ...

500 Type A souvenirs, and 3500 Type B souvenirs

3 0

2 years ago