Answer:
The minimum score required for an A grade is 83.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the z-score of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 72.3 and a standard deviation of 8.
This means that 
Find the minimum score required for an A grade.
This is the 100 - 9 = 91th percentile, which is X when Z has a pvalue of 0.91, so X when Z = 1.34.
The minimum score required for an A grade is 83.
-1 or option c is correct. Use the given functions to set up and simplify f(−2).
The total number of cookies baked by grandma = 96
Number of grandchildren = 8
As given, all cookies were evenly divided among 8 children, let us assume that everyone except Cindy got equal share. So on being divided equally, it becomes, 
cookies per children.
But, as mentioned that Cindy received 'c' cookies less, so let us suppose Cindy received 'x' cookies.
Expression becomes: 
Hence, Cindy received 12-c cookies.
To solve the problem, get the
percentage of each test by multiplying the score and the percentage then add it all up:
82 * .25 (highest test grade) + 65* .15 (lowest test grade) +
71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework
grade)
= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number
The answer to this question would be: <span>The new survey’s margin of error will be between 50% and 100% the size of the original survey’s margin of error.
A bigger sample will result in a narrower margin of error which is a good thing because your data will become more accurate. But twice size will not improve the margin into the half. It definitely became lower than 100% though
</span>
