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cricket20 [7]
3 years ago
14

Isabelle bought 12 bottles of water at $2 each

Mathematics
1 answer:
skad [1K]3 years ago
6 0
$24, 2 Times 12 = 24
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The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

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In the pictures down below<br><br>Can anyone help? Fractions and percents<br><br> 
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1st Picture:
3)- \frac{6}{7} +\frac {10}{11}&#10;\\\\LCD:77&#10;\\\\\frac{6}{7}* \frac{11}{11} +  \frac{10}{11}*\frac{7}{7}= \frac{66}{77} + \frac{70}{77}  = \frac{136}{77} = 1\frac{59}{77} &#10; \\  \\ 4) 3\frac{6}{7}* 2 \frac{1}{10}=  \frac{27}{7} * \frac{21}{10} = \frac{567}{70} =\frac{81}{10} = 8\frac{1}{10}&#10;\\\\5)2\frac{1}{2}+3\frac{1}{3}&#10;\\\\LCD: 6&#10;\\\\ 2\frac{3}{6} + 3\frac{2}{6} =5\frac{5}{6}&#10;\\\\6)5\frac{1}{8}*-6\frac{6}{11}=\frac{41}{8}* \frac{72}{11}=\frac{2952}{88}=\frac{369}{11}=33\frac{6}{11}

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1)80 percent of 80 = .8*80 =64&#10;\\\boxed{64}&#10;\\\\2)95percent of 100=.95*100=95&#10;\\\boxed{95}
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3 years ago
What is SOH CAH TOA?
vitfil [10]

Answer:

Soh= sin= opp/hyp cah= cos=adj/hyp

toa= tan= opp/adj

Step-by-step explanation:

4 0
2 years ago
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Pls help me I’ll give you 15 points
zaharov [31]

Answer:

number one is i thinks 10000000

Step-by-step explanation:

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2 years ago
How do you solve multi variable equations?​
Mekhanik [1.2K]
1. Understand what multi-variable equations are.

Two or more linear equations that are grouped together are called a system. That means that a system of linear equations is when two or more linear equations are being solved at the same time.
[1] For example:
• 8x - 3y = -3
• 5x - 2y = -1
These are two linear equations that you must solve at the same time, meaning you must use both equations to solve both equations.

2. Know that you are trying to figure out the values of the variables, or unknowns.

The answer to the linear equations problem is an ordered pair of numbers that make both of the equations true.
In the case of our example, you are trying to find out what numbers ‘x’ and ‘y’ represent that will make both of the equations true.

• In the case of this example, x = -3 and y = -7. Plug them in. 8(-3) - 3(-7) = -3. This is TRUE. 5(-3) -2(-7) = -1. This is also TRUE.

3. Know what a numerical coefficient is.

The numerical coefficient is simply the number that comes before a variable.[2] You will use these numerical coefficients when using the elimination method. In our example equations, the numerical coefficients are:

• 8 and 3 for the first equation; 5 and 2 for the second equation.


4. Understand the difference between solving with elimination and solving with substitution.

When you use elimination to solve a multivariable linear equation, you get rid of one of the variables you are working with (such as ‘x’) so that you can solve the other variable (‘y’). Once you find ‘y’, you can plug it into the equation and solve for ‘x’ (don’t worry, this will be covered in detail in Method 2).

• Substitution, on the other hand, is where you begin working with only one equation so that you can again solve for one variable. Once you solve one equation, you can plug in your findings to the other equation, effectively making one large equation out of your two smaller ones. Again, don’t worry—this will be covered in detail in Method 3.


5. Understand that there can be linear equations that have three or more variables.

Solving for three variables can actually be done in the same way that equations with two variables are solved. You can use elimination and substitution, they will just take a little longer than solving for two, but are the same process.
6 0
3 years ago
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