Answer:
The acceleration of Trout is largest.
Explanation:
Speed of Thomson's gazelle, v = 13 m/s in 3 s. Let us assumed that initial speed is 0. Acceleration is given by :
Speed of lion is 9.5 m/s in 10 s. Let us assumed that initial speed is 0. Acceleration is given by :
A trout can reach a speed of 2.8 m/s in 0.12 s. Let us assumed that initial speed is 0. Acceleration is given by :
It is clear that the acceleration of Thomson's gazelle, lion and trout is respectively. So, the acceleration of Trout is largest.
Answer:
Magnitude of Force : 0.8 N
Explanation:
We know that the velocity of this particle changes from 15ms⁻¹, or in other words 15m / s, to the respective velocity 25m / s over the course of 2.5 seconds. Given this information we can determine the acceleration of the particle,
a = v₁ - v₂ / t = 25 - 15 / 2.5 = 10 / 2.5 = 4m / s²
Knowing the acceleration we can calculate the magnitude of the force using the formula f = ma - Newton's second law of motion,
f = m a = 200g 4m / s² = 800 g m / s²
Remember however that Newtons are in the standard units kg m / s². Therefore we have to convert 800 g to kg to receive our solution,
800 g = 800 / 1000 kg = 0.8 kg,
Magnitude of Force = 0.8 N ; Solution = Option B