You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s a. Veloc
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when the ball hits the floor and bounces back the momentum of the ball changes.
the rate of change of momentum is the force exerted by the floor on it.
the equation for the force exerted is
f = rate of change of momentum
v is the final velocity which is - 3.85 m/s
u is initial velocity - 4.23 m/s
m = 0.622 kg
time is the impact time of the ball in contact with the floor - 0.0266 s
substituting the values
since the ball is going down, we take that as negative and ball going upwards as positive.
f = 189 N
the force exerted from the floor is 189 N
Let .
Normal force equals (using Newton's third law) .
, but
for all
(in order to start moving the break). Therefore
, solving for
: