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telo118 [61]
3 years ago
15

At what location in this diagram do the magnetic field lines show that the magnetic field is strongest ?

Physics
2 answers:
34kurt3 years ago
5 0

Answer: A or D I'd think D

Explanation: we're c is located the lines are all belong pulled towards the southern pole of the magnet while we're A is located it s between both poles.

RSB [31]3 years ago
3 0

Answer:

D is weakest

Explanation:

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What is the final step in the scientific method? 1. Conclusion 2. Analysis 3. Experiment 4. Observation
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If you throw a ball up with a velocity of 7 m/s, how long will it take for the ball to reach the top of its path?
nirvana33 [79]

Answer:

c. 0.71 [s]

Explanation:

To solve this problem we must use the following equation of kinematics.

v_{f} =v_{o} -g*t

where:

Vf = final velocity = 0 (because when the ball reaches the top, there is no movement)

Vo = initial velocity = 7 [m/s]

g = gravity acceleration = 9.81 [m/s²]

t = time [s]

Note: The negative sign of the equation means that the movement is againts the direction of the gravity acceleration.

0 = 7 - (9.81*t)\\t = 0.713 [s]

4 0
3 years ago
Is a 3D parallel flow necessarily irrotational?
satela [25.4K]

Answer:

No

Explanation:

We know that

Rationality in 3D flow is given as follows

\omega =\omega _xi+\omega _yj+\omega _zk

If ω is equal to zero then flow will be irrotational and if ω is not equal to zero then flow will be rotational .

So if flow is ir-rotational it means that the component of ω in x-direction,in y-direction and in z-direction direction should be zero.

So it is not necessarily that 3D parallel flow will be irrotaional.

3 0
3 years ago
Monochromatic light is incident on a grating that is 75 mmwide
statuscvo [17]

Answer:

Explanation:

Given

Grating Width w=75 mm

no of lines N=50,000 lines

inclination of second order maxima \theta =32.5^{\circ}

Condition of maxima For Diffraction grating

d\sin \theta =m\lambda

where d=Grating\ constant

\lambda =wavelength

m=order\ of\ maxima

d=\frac{width}{N}

d=\frac{75}{50,000}

d=0.0015\ mm

therefore for second order maxima wavelength of light is given by

\lambda =\frac{d\sin \theta }{m}

\lambda =\frac{0.0015\times \sin (32.5)}{2}

\lambda =403\times 10^{-6}\ m

\lambda =403\ nm

3 0
3 years ago
Which of the following quantities can be determined from a speed-time graph of a particle travelling in a straight line?
enot [183]

The answer is:

Both the distance traveled in a given time and the magnitude of the acceleration at a given instant


Hope I Helped!

8 0
3 years ago
Read 2 more answers
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