M = 30 g = 0.03 kg, the mass of the bullet
v = 500 m/s, the velocity of the bullet
By definition, the KE (kinetic energy) of the bullet is
KE = (1/2)*m*v²
= 0.5*(0.03 kg)*(500 m/s)² = 3750 J
Because the bullet comes to rest, the change in mechanical energy is 3750 J.
The work done by the wall to stop the bullet in 12 cm is
W = (1/2)*(F N)*(0.12 m) = 0.06F J
If energy losses in the form of heat or sound waves are ignored, then
W = KE.
That is,
0.06F = 3750
F = 62500 N = 62.5 kN
Answer:
(a) 3750 J
(b) 62.5 kN
3x + 1 ≤ 1
Subtract 1 from each side: 3x ≤ 0
Divide each side by 3 : <em>x ≤ 0</em>
Answer:
2. much hotter and much denser than its surface
Explanation:
We know that the temperature around the center of the Sun is about 1.57×10⁷ K and its density is about 162 g/cm³.
Now, the temperature and the density decrease as one moves outward from the center of the Sun, the temperature at the surface of the sun is about 5×10³ K and the density as an average in the surface is about 1.4 g/cm³.
Therefore the answer is:
2. much hotter and much denser than its surface.
I hope it helps you!
Have a nice day!
X=15! hope this helps! Also please look at my questions about the cannon ball!!! need help!
