What is the slope of the line? * 3 2 6 5 other: ______

Suppose the same quantity is measured but with a more precise method giving an average and standard deviation of 15.0 ± 2.5. how

abruzzese [7]

To solve this, we use the z test.

The formula:

z = (x – u) / s

where x is sample value = 20, u is the mean = 15, and s is the standard deviation = 2.5

z = (20 – 15) / 2.5

z = 2

Since we are looking for values greater than 20, this is right tailed test. We use the standard distribution tables to find for P.

P = 0.0228

Therefore:

number of students = 100 * 0.0228 = 2.28

2 to 3 students will get greater than 20 measurement

7 0

3 years ago

In January, Music Marathon priced all the compact discs (CD’s) at $20. In February, these same CD’s were discounted 50% and in M

skad [1K]

Answer:I think it would be $9

Step-by-step explanation:

50% of 20 is $10

10% of $10 is $1

Subtract 1 from 10, which gives you $9

3 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3>Solution:</h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

The area of rectangle is given as:

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

General form of quadratic equation is

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

2 years ago

Dean and his friends went to Aqua World Water Park, where they floated down the Lazy River for 1 2 of an hour. This was 1 4 of t

Kisachek [45]

1/2 of an hour is 30 minutes
That’s 1/4 of the total amount of time they spent in the park
So, 30 minutes x 4 would be 120 minutes or 2 hours which means they spent 2 hours at the water park

3 0

2 years ago

1/6 + 3/8 A. 4/6 B. 4/8 C. 4/14 D. 13/24

Naddika [18.5K]

Here is you're answer:

In order to get you're answer you need to find the common denominator then add.