Factor 16x2 + 121 over the set of complex numbers.
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1 answer:
Answer:
(4x - 11i)(4x -+11i)
Step-by-step explanation:
Factor as a difference of squares
a² - b² = (a - b)(a + b)
note that i² = - 1
Given
16x² + 121
= (4x)² - (11i)²
= (4x - 11i)(4x + 11i)
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