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3 years ago

How many different triangles can you make if you are given these three lengths for sides? 17cm, 23cm, and 13cm.

Mathematics

1 answer:

Natalija [7]3 years ago

7 0

Answer:

1 triangle can be formed

Step-by-step explanation:

We are given three side lengths, which are 17cm, 23cm, and 13cm. So, we can form the triangle when;

17 + 23 > 13

17 + 13 > 23

23 + 13 > 17

Since the above conditions are met, then we can form one triangle.

Now, each next triangle with the same sides lengths will be congruent to the first triangle by SSS postulate.

SSS postulate states that: If the three sides of a triangle are congruent to the three sides of another triangle, then the two triangles are congruent.

Thus, only 1 triangle can be formed.

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Three hundred seventeen kids went on a field trip last

arlik [135]

Answer:

310 kids/ 6 busses

310/6=51.6 so

52 or 51 kids on each bus.

3 0

2 years ago

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Solve:<br><br> a.x3+x2-8x - 12x+2<br> b. x3-4x2-3x + 18x-3<br> c. x2 + 4x + 4<br> d. x2 - 6x + 9

NeTakaya

<h2>Steps:</h2>

So firstly, this function is asking us to divide f(x) by g(x) so let's set that up as such:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\div \frac{x-3}{x+2}$

Next, remember that <u>dividing by a number is the same as multiplying by its reciprocal.</u> To find the reciprocal of a number, flip the numerator and denominator around. With this info, flip the second fraction to it's reciprocal and change the sign to multiplication:

$(\frac{f}{g})(x)=\frac{x^2-x-6}{1}\times \frac{x+2}{x-3}$

Next, we are going to factor x² - x - 6. Firstly, what two terms have a product of -6x² and a sum of -x? That would be -3x and 2x. Replace -x with 2x - 3x:

$(\frac{f}{g})(x)=\frac{x^2+2x-3x-6}{1}\times \frac{x+2}{x-3}$

Next, factor x² + 2x and -3x - 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

$(\frac{f}{g})(x)=\frac{x(x+2)-3(x+2)}{1}\times \frac{x+2}{x-3}$

Now you can rewrite it as:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)}{1}\times \frac{x+2}{x-3}$

Next, multiply:

$(\frac{f}{g})(x)=\frac{(x-3)(x+2)^2}{x-3}$

Next, divide:

$(\frac{f}{g})(x)=(x+2)^2$

And lastly, simplify:

A good tip: $(x+y)^2=x^2+2xy+y^2$

$(\frac{f}{g})(x)=x^2+4x+4$

<h2>Answer:</h2>

<u>The correct option is C. x² + 4x + 4.</u>

7 0

3 years ago

What value of x is in the solution set of 3(x – 4) ≥ 5x + 2? <br><br> –10<br> –5<br> 5<br> 10

emmasim [6.3K]

<u>Answer:</u>

The value of x is in the solution set of 3(x – 4) ≥ 5x + 2 is -10

<u>Solution:</u>

Need to determine which value of x from given option is solution set of 3(x – 4) ≥ 5x + 2

Lets first solve 3(x – 4) ≥ 5x + 2

3(x – 4) ≥ 5x + 2

=> 3x – 12 ≥ 5x + 2

=> 3x – 5x ≥ 12 + 2

=> -2x ≥ 14

=> -x ≥ 7

=> x ≤ -7

All the values of x which are less than or equal to -7 is solution set of 3(x – 4) ≥ 5x + 2. From given option there is only one value that is -10 which is less than -7

Hence from given option -10 is solution set of 3(x – 4) ≥ 5x + 2.

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3 years ago

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Use the information below to answer the question: The Tigers scored 3

Paraphin [41]

Answer:

they either scored 18 or 9 points from the field goals but i think it is the 9 point if i'm wrong then it is the other one

Step-by-step explanation:

3 0

3 years ago

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