Diagonal of the parallelogram divides the parallelogram in to two equal areas.
So area of parallelogram = 2(area of triangle)
According to the given diagram,
AB= 8, AD = 5 and BD = 11
So according to the Heron's formula,
Area of triangle = 
and a, b and c are the three sides of the triangle
Area of triangle ABD =
So, area of parallelogram ABCD = 2(area of triangle ABD)
area of parallelogram ABCD = 2 (18.33)
area of parallelogram ABCD = 36.66
area of parallelogram ABCD = 36.7 sq. units
Answer:
good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2
but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1
B=t-am is the correct answer:)
Answer:
I believe its 17, this is a 90 degree angle, so 90-73=17
Step-by-step explanation:
