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gulaghasi [49]
3 years ago
6

En un juego se tiene una ficha, donde un lado dice ganar y otro dice perder. Si se ha lanzado 3 veces la ficha y en todos a sali

do el lado que dice ganar. ¿Cuál es la probabilidad de que en el cuarto lanzamiento también salga el lado que dice ganar?
Mathematics
1 answer:
Alexxandr [17]3 years ago
5 0

Answer:

no existe una probabilidad ya que es un juego de azar pero si queres la cuarta victoria deberias calcular muchas cosas como el angulo para tirar la ficha y calcular la fuerza etc

Step-by-step explanation:

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jonny [76]
First, we find the slope of the given line.

<span>3x − 4y = 7

-4y = -3x + 7

y = (3/4)x - 7/4

The slope of the given line is 3/4.
The slope of the parallel line is also 3/4.

Now we need the equation of the line that has slope 3/4 and passes through point (-4, -2),

We use the point-slope form of the equation of a line.

y - y1 = m(x - x1)

y - (-2) = (3/4)(x - (-4))

y + 2 = (3/4)(x + 4)     <---- check option E. Is the fraction 3/4 not there?

y + 2 = (3/4)x + 3

y = (3/4)x + 1

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3x - 4y = -4    <------ this is choice B.
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Step-by-step explanation:

-\frac{1}{4}+2\frac{1}{4}y+2-y=y+2

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10

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