I think with the next procedue I can help you a lot with it:
if
R = 50%
<span>x = Blood Alcohol Content (BAC)
</span>Then
<span>50= 6 e^(12.77x) </span>
<span>50/6 = e^(12.77x) </span>
<span>ln(50/6) = 12.77x </span>
<span>x = ln(50/6)/12.77 </span>
<span>x = 0.166
</span>
I hope this can help you through
Answer:
Could either be D or B but personally I think it is B
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