3 years ago

Can someone help me? Solve for x.

Mathematics

1 answer:

Luda [366]3 years ago

3 0

I think the answer is 24. Let me know if I helped!

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How do you solve and show work for <br>624 divided by 8<br>

natali 33 [55]

pls mark as brainlist

Step-by-step explanation:

624 divided by 8 = 78

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3 years ago

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A right-angled triangle has shorter side lengths exactly c^2-b^2 and 2bc units respectively, where b and c are positive real num

yKpoI14uk [10]

Answer: hypotenuse = $c^{2} + b^{2}$

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ( $s_{1},s_{2}$ ) of the right triangle, .i.e.:

$h^{2} = s_{1}^{2} + s_{2}^{2}$

In this question:

$s_{1}$ = $c^{2}-b^{2}$

$s_{2} =$ 2bc

Substituing and taking square root to find hypotenuse:

$h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}$

Calculating:

$h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}$

$h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}$

$c^{4}+b^{4}+2b^{2}c^{2}$ = $(c^{2}+b^{2})^{2}$ , then:

$h=\sqrt{(c^{2}+b^{2})^{2}}$

$h=(c^{2}+b^{2})$

Hypotenuse for the right-angled triangle is $h=(c^{2}+b^{2})$ units

3 0

3 years ago

Please help me on this!

Tanya [424]

Answer: A. 4.
Explanation: solving graphically

6 0

1 year ago

Will you check my math its supposed to be a face!

LUCKY_DIMON [66]

It looks like a face to me

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3 years ago

What is the LCM of 3and 6

kupik [55]

Answer:

L.c.m of 3 and 6 is 6

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