(5/7) / (8/9)...when dividing fractions, flip what u r dividing by, then multiply
5/7 * 9/8 =
45/56 <==
I’m pretty sure it’s 11. So answer D
The height of the trapezoid is ![h=11.2](https://tex.z-dn.net/?f=h%3D11.2)
Explanation:
AKLM is a trapezoid.
The measurements of the trapezoid are AK=13, LM=14, KL=5, AM=20
We need to find the height of the trapezoid.
Let M' be a point on AM that is 5 units toward point A from M.
Let B be a point on AM such that KB⊥AM. Let x = AB; then BM' = 15 -x.
Using Pythagorean theorem, we have,
--------(1)
-----------(2)
Subtracting the two equations, we have,
![\left(225-30 x+x^{2}+h^{2}\right)-\left(x^{2}+h^{2}\right)=196-169](https://tex.z-dn.net/?f=%5Cleft%28225-30%20x%2Bx%5E%7B2%7D%2Bh%5E%7B2%7D%5Cright%29-%5Cleft%28x%5E%7B2%7D%2Bh%5E%7B2%7D%5Cright%29%3D196-169)
Simplifying, we get,
![225-30x=27](https://tex.z-dn.net/?f=225-30x%3D27)
Subtracting both sides of the equation by 225, we get,
![30x=198](https://tex.z-dn.net/?f=30x%3D198)
Dividing by 30, we get,
![x=6.6](https://tex.z-dn.net/?f=x%3D6.6)
Substituting
in the equation
, we get,
![(6.6)^{2}+h^{2}=169](https://tex.z-dn.net/?f=%286.6%29%5E%7B2%7D%2Bh%5E%7B2%7D%3D169)
![43.56+h^2=169](https://tex.z-dn.net/?f=43.56%2Bh%5E2%3D169)
![h=\sqrt{125.44}](https://tex.z-dn.net/?f=h%3D%5Csqrt%7B125.44%7D)
![h=11.2](https://tex.z-dn.net/?f=h%3D11.2)
Thus, the height of the trapezoid is ![h=11.2](https://tex.z-dn.net/?f=h%3D11.2)
The answer would be $17.32. The tip would be $2.14. And the sales tax would be $0.93.
If you add them altogether you get $17.32
Answer:
= 298/11
Step-by-step explanation:
3x + 5y = 2 | ×2 |
2x - 4y = 20 | ×3 |
6x + 10y = 4
6x - 12y = 60
____________--
22y = -56
y = -56/22
y = -28/11
3x + 5y = 2 | ×4 |
2x - 4y = 20 | ×5 |
12x + 20y = 8
10x - 20y = 100
_____________+
22x = 108
x = 108/22
x = 54/11
5x - y
= 5(54/11) - (-28/11)
= 270/11 + 28/11
= 298/11