Answer:
Zero-day exploits
Explanation:
Zero-day exploits refers to recently found vulnerabilities in a computer software program that has been in existence but was hitherto not known and addressed by the software security experts, however, these vulnerabilities were known to hackers. While the existence of these "loop-holes" in the software can go on unnoticed for several years, hackers can take advantage of it to cause harm to the computers' programs and data.
When these attacks occur, it is called a zero-day because the attack took place on the very day that the loop-hole was discovered in the software. So exploitation has already taken place before a fix is carried out.
Answer:
Explanation:
Click the Data option.
Click on Named Range. This will open the 'Named ranges' pane on the right.
Click on the 'Add a range' option.
Enter the name you want to give the column (“Sales” in this example)
Make sure the column range is correct. ...
Click on Done.
Answer:
The three Linux distributions are Arch Linux, Ubuntu and Fedora. In order to get more detailed information go to the wikipedia page of comparision of linux distributions.
Strengths and Features of these three are attached.
The two linux newsgroups are
1) Comp.os.linux.announce
2)comp.os.linux.networking
Explanation:
CORRECT QUESTION:
For the given program, how many print statements will execute?
public static void printShippingCharge(double weight) { if((weight > 0.0) && (weight <= 10.0)){ System.out.println(weight * 0.75); }
else if((weight > 10.0) && (weight <= 15.0)) { System.out.println(weight * 0.85); }
else if((weight > 15.0) && (weight <= 20.0)) { System.out.println(weight * 0.95); } }
public static void main(String args[]) {
printShippingCharge(18);
printShippingCharge(6);
printShippingCharge(25); }
Answer:
Two of the print statements will output values
Explanation:
These two calls to the printShippingCharge are the ones that will output values: printShippingCharge(18); and printShippingCharge(6);
The first if statement is true when the value of weight is 6 (weight > 0.0) && (weight <= 10.0)
The Third if statement is true when weight is 18 (weight > 15.0) && (weight <= 20.0)
NOTE: That I made correction to the variable weight. The question isn't consistent with the variable name. It used weight and itemWeight at different points this will lead to a compiller error
