Answer:
(f+g)(x) = 13x + 3
Step-by-step explanation:
Rewrite f(x)=2x+7 and g(x)=11x-4 in columns, as follows:
f(x)=2x+7
+g(x)=11x-4
----------------
Now add each column separately.
f(x)+g(x) = (f+g)(x) ("the sum of functions f and g")
2x + 11x = 13x, and, finally, 7-4 = 3.
Therefore,
f(x)=2x+7
+g(x)=11x-4
----------------
(f+g)(x) = 13x + 3
<span>A) 11c - 2d = -2
B) c + 8d = 8
</span><span>B) c = 8 - 8d then substitute this into A)
</span><span>A) 88 -88d - 2d = -2
A) 90 = 90d
d = 1
c = 0
</span>
So the diagonal of cube
this was a practice act question so her's the answer
look at the cube through one of the faces
you will see the diagonal as the hypotonuse of a triangle
and also a triangle on the floor (look at attachment)
the ,diagonal is 28
a^2+b^2=28^2
a=b since it is a cube
remember that this is a 45,45 triangle so therefor
a=b=x
c=x√2 so
28=x√2
divide both sides by √2
28/(√2)=x
the diagonal on the floor is 28/(√2)
the sides of the triangle form another 45 45 90 triangle with 28/(√2) as hyponuse so
a=b=x
c=x√2=28/(√2)
solve for x
x√2=28/(√2)
divide both sides by √2
same as mujlitply both sides by 1/(√2) so
28/(√2) times 1/(√2)=28/(2)=14
the answer of 1 diagonal is 14 cm
the answer is 14cm
Answer:
SOLVE FOR RECTANGLE
Area: lw (length times width)
rectangle: lw (6x6)
AREA=36in
SOLVE FOR TRIANGLE B
Area: A=hbxb/2
A=hb/b2=6·6/2=18
TRIANGLE B=18in
SOLVE FOR TRIANGLE A
Area: A=hbxb/2
The height looks half the height as the other triangle
A=hb/b2=3·4/2=6
TRIANGLE A=6in
{ADD}
36+18+6
TOTAL: 60in
Step-by-step explanation:
HOPE THAT HELPED!!!
The answer is the first one. 524.96 - 32.50 + x ≥ 500; x ≥ $7.54