Answer:
(m + 3) (m - 6)
Step-by-step explanation:
Simplify the following:
m^2 - 3 m - 18
The factors of -18 that sum to -3 are 3 and -6. So, m^2 - 3 m - 18 = (m + 3) (m - 6):
Answer: |
| (m + 3) (m - 6)
It’s a 50/50 chance since there is only 2 sides. (1?2)
Answer:
60%
Step-by-step explanation:
You could make a fraction to help solve for the answer. The denominator is 25 because you add 4 + 15 + 6. The numerator is 15, because it is the number of roses. 15/25 as a percent is 60% because you just times both the numerator and denominator by 4.
We start with the expression at the left of the equation.
We can combine the terms as:
![\begin{gathered} \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}} \\ \frac{2+\sqrt[]{3}}{\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})}-\frac{2-\sqrt[]{3}}{\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}}}\cdot\frac{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D-%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%20%5C%5C%20%5Cfrac%7B2%2B%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%5Ccdot%5Cfrac%7B%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D-%5Cfrac%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7B%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%5Ccdot%5Cfrac%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%20%5C%5C%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29-%282-%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%20%5Cend%7Bgathered%7D)
We can now apply the distributive property for the both the numerator and denominator. We can see also that the denominator is the expansion of the difference of squares:
![\begin{gathered} \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})-(2-\sqrt[]{3})\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{(\sqrt[]{2})^2-(\sqrt[]{2-\sqrt[]{3}}))^2} \\ \frac{(2+\sqrt[]{3})\cdot(\sqrt[]{2}-\sqrt[]{2-\sqrt[]{3}})+(\sqrt[]{3}-2)\cdot(\sqrt[]{2}+\sqrt[]{2-\sqrt[]{3}})}{2^{}-(2-\sqrt[]{3})^{}} \\ \frac{\sqrt[]{2}\cdot(2+\sqrt[]{3})-\sqrt[]{2-\sqrt[]{3}}\cdot(2+\sqrt[]{3})+\sqrt[]{2}\cdot(\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}\cdot(\sqrt[]{3}-2)}{2-2+\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2+\sqrt[]{3}+\sqrt[]{3}-2)+\sqrt[]{2-\sqrt[]{3}}(-2-\sqrt[]{3}+\sqrt[]{3}-2)}{\sqrt[]{3}} \\ \frac{\sqrt[]{2}(2\sqrt[]{3})+\sqrt[]{2-\sqrt[]{3}}(-4)}{\sqrt[]{3}} \\ 2\sqrt[]{2}-4\frac{\sqrt[]{2-\sqrt[]{3}}}{\sqrt[]{3}} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29-%282-%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B%28%5Csqrt%5B%5D%7B2%7D%29%5E2-%28%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%29%5E2%7D%20%5C%5C%20%5Cfrac%7B%282%2B%5Csqrt%5B%5D%7B3%7D%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%2B%28%5Csqrt%5B%5D%7B3%7D-2%29%5Ccdot%28%5Csqrt%5B%5D%7B2%7D%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%29%7D%7B2%5E%7B%7D-%282-%5Csqrt%5B%5D%7B3%7D%29%5E%7B%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%5Ccdot%282%2B%5Csqrt%5B%5D%7B3%7D%29-%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ccdot%282%2B%5Csqrt%5B%5D%7B3%7D%29%2B%5Csqrt%5B%5D%7B2%7D%5Ccdot%28%5Csqrt%5B%5D%7B3%7D-2%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%5Ccdot%28%5Csqrt%5B%5D%7B3%7D-2%29%7D%7B2-2%2B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%282%2B%5Csqrt%5B%5D%7B3%7D%2B%5Csqrt%5B%5D%7B3%7D-2%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%28-2-%5Csqrt%5B%5D%7B3%7D%2B%5Csqrt%5B%5D%7B3%7D-2%29%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%20%5Cfrac%7B%5Csqrt%5B%5D%7B2%7D%282%5Csqrt%5B%5D%7B3%7D%29%2B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%28-4%29%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5C%5C%202%5Csqrt%5B%5D%7B2%7D-4%5Cfrac%7B%5Csqrt%5B%5D%7B2-%5Csqrt%5B%5D%7B3%7D%7D%7D%7B%5Csqrt%5B%5D%7B3%7D%7D%20%5Cend%7Bgathered%7D)
We then can continue rearranging this as:
We can calculate (62 + 90) / 2 = 76. it's <span>known that 95% lies between the mean and twice the standard deviation. </span><span>if the mean is "μ" and the standard deviation is "σ": </span><span>μ-2σ and μ+2σ. i</span><span>f μ=76, then </span><span>76+2σ = 90, so 2σ = 14, so σ = 7.
</span>
<span>the mean is 76 and the standard deviation 7. </span>
