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eimsori [14]
3 years ago
5

Is the problem, 6y-2x=10 in standard form?​

Mathematics
2 answers:
BartSMP [9]3 years ago
7 0
Correct answer is 2x-6y=-10
serious [3.7K]3 years ago
4 0

Answer:

No.

Step-by-step explanation:

Standard form is

ax + by = c.

So 6y - 2x = 10 is not in standard form.

Correct  is -2x + 6y = 10.

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Plz help. Simplifying simplify the answers
galben [10]
9/32
1/3
1/9
7/18
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5/44
Still in fractions?
6 0
3 years ago
Read 2 more answers
I NEED HELP ASAP write an equivalent unit rate to running 5/4 a mile in 9 minutes
svetlana [45]

Answer:

The unit rate is 0. 14 miles per minute.

Hence, option a is correct.

Step-by-step explanation:

Given

Running of 5/4 a mile in 9 minutes.

To determine

The unit rate = ?

Given that the running 5/4 a mile in 9 minutes.

i.e.

Miles covered in 9 minutes = 5/4 or 1.25 miles

Miles covered in 1 minute = 1.25/9

                                           = 0. 14 miles per minute

Therefore, we conclude that:

The unit rate is 0. 14 miles per minute.

Hence, option a is correct.

6 0
2 years ago
Explain the areas in which you will find integration to be significant in your day to day work as an EHT.
andrey2020 [161]

Answer:

Step-by-step explanation:

An EHT is an Environmental Health Technician. Integration (Integral Calculus, if that's what you mean) will be applied to an Environmental Health Technician's job in the following way:

1. In the analysis or examination of samples from an environment, such as soil sample, water sample, domestic waste sample, septic waste sample, etc.

Essentially, Integral Calculus (and other forms of Maths) must be studied, before a person is able to be an Environmental Health Technician.

Degrees in any of the following fields are a necessary criterion;

- Applied Science

- Public Health

- Environmental Science

- Biochemistry

- Health Data Analysis

7 0
3 years ago
QUESTION 11
notsponge [240]

Answer:

8

Step-by-step explanation:

3( 2 + 2 ) - 4

3( 4 ) - 4

12-4

8

3 0
3 years ago
Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
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