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Irina18 [472]
3 years ago
11

How do I andser this. I’m stuck

Mathematics
1 answer:
Mars2501 [29]3 years ago
8 0
A= 3:5
b= 12:20
c= yes because 3” 3+2=5 n in the beginning of the problem it said end of season
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A rectangle has 3 square feet and width 1/2 foot. What is the length of the rectangle
Yakvenalex [24]

Answer:

We Know, Area = Length * Width

Here, A = 3

W = 1/2

Substitute it into the expression,

3 = L * 1/2

L = 3/ 1/2

L = 3/2 ft²

So, the length of the rectangle would be 3/2 ft²

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3 years ago
GIVING BRAINLIEST!!!!!
Mashutka [201]

Answer:

D' : (2, 1)

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Step-by-step explanation:

6 0
1 year ago
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I need help with Q9 c, I’ve done a and b if it helps, b=325 but I am just stuck on question 9C, I know the answer is 500N (as it
777dan777 [17]

Step-by-step explanation:

I know you've already done parts a and b, but I'll show the work for that before I do c.

Draw two free body diagrams, one for the car and one for the trailer.  The car pulls the trailer forward with a tension force T, so the trailer pulls backward on the car with an equal and opposite force T.

The car also has a 1200 N forward force from the engine, and a 200 N backwards force from resistance.

The trailer has a backwards resistance force of 100 N.

Sum of forces on the car:

∑F = ma

1200 − 200 − T = 900a

1000 − T = 900a

Sum of forces on the trailer:

∑F = ma

T − 100 = 300a

To solve the system of equations, first add the equations together.

1000 − 100 = 1200a

900 = 1200a

a = 0.75 m/s²

Plug back into either equation to find the tension force:

T = 325 N

Now for part c, draw new free body diagrams for the car and trailer.  This time, the car is pushing back on the trailer to slow it down.  So the trailer is pushing forward on the car with an equal and opposite force.  The magnitude of that tension force is given to be 100 N.

The car also has a backwards 200 N force from resistance, and a backwards brake force F.

The trailer has a backwards 100 N force from resistance.

Sum of forces on the car:

∑F = ma

100 − 200 − F = 900a

-100 − F = 900a

Sum of forces on the trailer:

∑F = ma

-100 − 100 = 300a

-200 = 300a

a = -⅔

Plugging into the first equation:

-100 − F = 900 (-⅔)

-100 − F = -600

F = 500 N

4 0
2 years ago
3. What are the coordinates of the points of tangency of the two tangent lines through the point (1,1) each tangent to the circl
VashaNatasha [74]

Answer:y+x=2    

Step-by-step explanation:

Given

equation of circle x^2+y^2=1

Equation of tangent passing through (1,1)

Slope of tangent is given by differentiating equation of circle

2x+2y\frac{\mathrm{d} y}{\mathrm{d} x}=0

\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{-x}{y}

at (x,y)=(1,1)

\frac{\mathrm{d} y}{\mathrm{d} x}=\frac{-1}{1}

Equation of line with slope

m=\frac{y-y_0}{x-x_0}

-1=\frac{y-1}{x-1}

y+x=2    

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2 years ago
The giraffe is 15 feet tall. she is 2 1/2 times as tall as the elephant. how tall is the elephant?
salantis [7]
The giraffe is about 5 feet tall
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3 years ago
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