Two sides of an isosceles triangle measures 10 and 10. What is true about the third side?

The admissions director from Big City University found that (107.8, 116.2) is a 95% confidence interval for the mean IQ score of

katen-ka-za [31]

Answer: The explanation is correct.

Step-by-step explanation:

The interpretation of 95% confidence interval for population mean is that "A person can be 95% sure that the true population mean lies in it."

Given : The admissions director from Big City University found that (107.8, 116.2) is a 95% confidence interval for the mean IQ score of all freshmen.

Interpretation: The admissions director can be 95% sure that the true population mean IQ score of all freshmen lies in (107.8, 116.2).

i.e. There is a 95% probability (chance) that the interval from 107.8 to 116.2 contains μ.

Hence, the explanation is absolutely "correct" .

7 0

3 years ago

Is the relationship linear, exponential, or neither?

kati45 [8]

Answer:

Neither linear nor exponential

Step-by-step explanation:

To check for a linear relationship. Find slope.

slope= (-1 - (-2)) / ( 5 - 2) = 1/3

check other points

slope = (1 - (-1) )/ (8 - 5) = 2/3

check more

slope = (4 - 1) / (11 - 8) = 3/ 3 = 1

Nope.

try assuming an exponential:

y = c * (a^x)

-2 = c* (a^2); -2/c = a^2

-1 = c *(a ^5); -1/c = a^5

1 = c * (a^8), 1/c = a^8

(-2/c)^4 = a^8 = 1/c

16/(c^4) = 1/c

c^3 = 16, then a = root (-2/ cube-root(16) )

The change from negative to postive would not work for y = c(a^x)

so...

assume y = a^x + k

-2 = a^2 + k

-1 = a^5 + k

... I would say neither..

6 0

3 years ago

Tammy rents an apartment close to her school campus. The amount that she spends on rent is given by the equation r = 355m, where

inna [77]

answer is c because if it's not a and b then the only answers will be c and d and d is the same as the number so it's c

8 0

3 years ago

A population of bees is decreasing. The population in a particular region this year is 1,250. After 1 year, it is estimated tha

8_murik_8 [283]

To model this situation, we are going to use the decay formula: $A=Pe^{rt}$
where
$A$ is the final pupolation
$P$ is the initial population
$e$ is the Euler's constant
$r$ is the decay rate
$t$ is the time in years

A. We know for our problem that the initial population is 1,250, so $P=1250$ ; we also know that after a year the population is 1000, so $A=1000$ and $t=1$ . Lets replace those values in our formula to find $r$ :
$A=Pe^{rt}$
$1000=1250e^{r}$
$e^{r}= \frac{1000}{1250}$
$e^{r}= \frac{4}{5}$
$ln(e^{r})=ln( \frac{4}{5} )$
$r=ln( \frac{4}{5} )$
$r=-02231$

Now that we have $r$ , we can write a function to model this scenario:
$A(t)=1250e^{-0.2231t}$ .

B. Here we are going to use a graphing utility to graph the function we derived in the previous point. Please check the attached image.

C.
- The function is decreasing
- The function doe snot have a x-intercept
- The function has a y-intercept at (0,1250)
- Since the function is decaying, it will have a maximum at t=0:
$A(0)=1250e^{(-0.2231)(0)$
$A_{0}=1250e^{0}$
$A_{0}=1250$
- Over the interval [0,10], the function will have a minimum at t=10:
$A(10)=1250e^{(-0.2231)(10)$
$A_{10}=134.28$

D. To find the rate of change of the function over the interval [0,10], we are going to use the formula: $m= \frac{A(0)-A(10)}{10-0}$
where
$m$ is the rate of change
$A(10)$ is the function evaluated at 10
$A(0)$ is the function evaluated at 0
We know from previous calculations that $A(10)=134.28$ and $A(0)=1250$ , so lets replace those values in our formula to find $m$ :
$m= \frac{134.28-1250}{10-0}$
$m= \frac{-1115.72}{10}$
$m=-111.572$
We can conclude that the rate of change of the function over the interval [0,10] is -111.572.

7 0

3 years ago

How do I do it ?skskskksksk help

ivanzaharov [21]

Answer:

lol you deleted my answer loser

Step-by-step explanation:

8 0

3 years ago