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Klio2033 [76]
3 years ago
11

Two sides of an isosceles triangle measures 10 and 10. What is true about the third side?

Mathematics
1 answer:
zvonat [6]3 years ago
6 0
The 3rd side is not the same length of the first 2 sides.
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Please answer this question.i would really apreciate it
mart [117]
What is the question?
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3 years ago
What is the distance ?
aleksklad [387]

The solution is you need to subtract the y axis and x axis

8 0
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Hello i need help with question 5 asap!!
sergeinik [125]

Answer:

  arc DB length = 14π feet

Step-by-step explanation:

Assuming point A is the center of the circle, arc DC has measure 180°. Arc DB has measure 40° less, so is 140°. Since you want this in terms of π, we need to convert the degree measure to radians. We do that by multiplying by (π/180) radians per degree:

  arc DB = 140° = 140°(π/180°) radians

__

Now that we know the arc measure in radians, we can find the length of the arc. It is given by the formula ...

  s = rθ

where r represents the radius and θ is the measure of the arc in radians.

The arc length is ...

  s = (18 ft)(7π/9) = 14π ft

Arc DB has a length of 14π feet.

4 0
4 years ago
Marsha wants to determine the vertex of the quadratic function f(x) = x2 – x + 2. What is the function’s vertex?
BaLLatris [955]

Answer:

Vertex = (\frac{1}{2},\frac{7}{4})

Step-by-step explanation:

Given

f(x) = x^2 - x +2

Required

The vertex

We have:

f(x) = x^2 - x +2

First, we express the equation as:

f(x) = a(x - h)^2  +k

Where

Vertex = (h,k)

So, we have:

f(x) = x^2 - x +2

--------------------------------------------

Take the coefficient of x: -1

Divide by 2: (-1/2)

Square: (-1/2)^2

Add and subtract this to the equation

--------------------------------------------

f(x) = x^2 - x +2

f(x) = x^2 - x + (-\frac{1}{2})^2+2  -(-\frac{1}{2})^2

f(x) = x^2 - x + \frac{1}{4}+2  -\frac{1}{4}

Expand

f(x) = x^2 - \frac{1}{2}x- \frac{1}{2}x + \frac{1}{4}+2  -\frac{1}{4}

Factorize

f(x) = x(x - \frac{1}{2})- \frac{1}{2}(x - \frac{1}{2})+2  -\frac{1}{4}

Factor out x - 1/2

f(x) = (x - \frac{1}{2})(x - \frac{1}{2})+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+2  -\frac{1}{4}

f(x) = (x - \frac{1}{2})^2+ \frac{8 -1 }{4}

f(x) = (x - \frac{1}{2})^2+ \frac{7}{4}

Compare to: f(x) = a(x - h)^2  +k

h = \frac{1}{2}

k = \frac{7}{4}

Hence:

Vertex = (\frac{1}{2},\frac{7}{4})

8 0
3 years ago
Read 2 more answers
PLS help ME!!!!<br> Simplify the expression
Vanyuwa [196]

Answer: -2.1p + 1.7

2.4 - 6p - 0.7 + 3.9p

Subtract 6p from 3.9p. (-2.1p)

Subtract 0.7 from 2.4. (1.7)

5 0
3 years ago
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