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3 years ago

Select the correct answer.

Mathematics

2 answers:

almond37 [142]3 years ago

6 0

12 divided by 3 is 4 so to make it equivalent you would time 4 by 4 which is 16 x=16

Crazy boy [7]3 years ago

3 0

Answer:

Step-by-step explanation:

to get from 3/4 to 12/x you gotta multiple 3 times 4 which is 12 so the bottom multiple that by 4 also which 4 x 4 is 16

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I think it's A on edge.

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3 years ago

Given h(x) = 4x + 5 solve for when h(x) = 9 .

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Answer:

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3 years ago

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mr_godi [17]

Hey there Jnorman1287.

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4 years ago

A medical researcher wants to measure the effects of a new drug on cholesterol levels using a hypothesis test. The target is a 3

maria [59]

Answer: e. test for a difference in two population means

Step-by-step explanation:

Since the researcher takes a random sample of patients and measures their cholesterol levels before and after a treatment cycle of the drug, then the two samples are matched pairs. The difference between both samples would be determined and the mean and standard deviation of this difference is calculated. This would be used to determine the test statistic.

Therefore, the type of hypothesis test that they should use is

e. test for a difference in two population means

8 0

3 years ago

Suppose that textbook weights are normally distributed. You measure 33 textbooks' weights, and find they have a mean weight of 7

AleksAgata [21]

Answer:

$75-2.58\frac{13.3}{\sqrt{33}}=69.027$

$75+2.58\frac{13.3}{\sqrt{33}}=80.793$

And the 95% confidence interval would be between (69.027;80.793)

Step-by-step explanation:

Information given

$\bar X=75$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=13.3$ represent the population standard deviation

n=33 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=33-1=32$

The Confidence level is 0.99 or 99%, the significance would be $\alpha=0.01$ and $\alpha/2 =0.005$ , the critical value for this case would be $z_{\alpha/2}=2.58$

And replacing we got:

$75-2.58\frac{13.3}{\sqrt{33}}=69.027$

$75+2.58\frac{13.3}{\sqrt{33}}=80.793$

And the 95% confidence interval would be between (69.027;80.793)

6 0

3 years ago