Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
690
12×36 + 258 = 690 For extending to 20 characters
When dividing 0.006 divided by 0.024 it becomes 0.025, i did it by calculator so dont give me credit for this lol
First multiply everything inside the brackets by seven
7x^4-42+3
Then solve what you can
7x^4-39
You an't solve it further. Is this what you mean? X to the fourth power?
