If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
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Answer:
ring volume is 12cm3
Step-by-step explanation:
Lr ccm=volume of water and ring - Volume of water
ring cubic centimeters =x
x=9.2cm*4.5cm*7cm - 8.8cm*4.5cm*7cm
x=289.2cm3 - 277.2cm3
x=12cm3
Answer:
The correct answer is option C, 228 feet
Step-by-step explanation:
As per Newton’s third law of motion:
V2 – U2 = 2 x a x S
Where V = final velocity
U = Initial Vlocity
a = acceleration (-ve)
S= distance travelled
V= 0 mph
U= 55 mph = 80.6667 ft /sec
0 – (80.6667 ft /sec)2 = 2 x (-g/2) x S
S = (80.6667 ft /sec)2 /(32.2 feet per second per second x0.5)
S = 202.1 feet
So the most nearest option is option C
Answer:
5(3x - 4)
Step-by-step explanation:
5(3x - 4)
use the distributive property
15x - 20
so its correct
