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VMariaS [17]
2 years ago
5

Please solve with explanation

Mathematics
1 answer:
garik1379 [7]2 years ago
4 0

Answer:

a. 49/2

b. -2/9

If I make any mistakes, I'm sorry.

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Verify that the points are the vertices of a parallelogram, and find its area. A(1, 1, 3), B(2, −5, 6), C(4, −2, −1), D(3, 4, −4
almond37 [142]

Answer:

Area = 71.3 sq unit

Step-by-step explanation:

a) We will use properties of parallelogram to verify the given vertices.

Property: Have a pair of parallel opposite sides

Hence, vectors AB AD BD BC CD AC. A pair should be parallel:

vectors

AB = A - B = (1, 1 , 3) - ( 2 , -5 , 6 ) = (-1 , 6 , -3)

AD = A - D = (1, 1 , 3) - (3, 4 , -4) = (-2 , -3 , 7)

BC = B - C = (2 , -5 , 6) - (4, -2 , -1) = (-2 ,-3 , 7)

CD = C - D = (4, -2 , -1) - (3, 4 , -4) = (1 , -6 , 3)

Hence we can see  that AB //CD and AD // BC as their unit vector co-efficents are identical/scalar multiple of each other.

b)

Equation of line AB = (1,1,3) + t*(-1 , 6 , -3 )

Point E = (1-t , 1+6t , 3 -3t) ... denotes an position of point E on line AB.

Choose a point on line CD, lets suppose C = ( 4 , -2 , -1 )

Vector EC = ( 1-t , 1+6t , 3-3t ) - (4 , -2 , -1 ) = (-3 -t , 3 +6t , 4 -3t)

For EC to be perpendicular to AB then dot product of AB . EC = 0

Hence,

EC . AB = -1 * (-3-t) -2*(3+6t) -3*(4-3t) = 0

3 + t -6 -12t -12+9t = 0

-2t-3 = 0

t = -3/2

Vector EC = (-3 -t , 3 +6t , 4 -3t) = (-1.5 , -6 , 8.5)

Area = magnitude (AB) * magnitude (EC)

Area = sqrt ((-1)^2 + 6^2 + (-3)^2) * sqrt ((-1.5)^2 + 6^2 + (8.5)^2)

Area = sqrt (46) * sqrt (442) / 2

Area = 71.3 unit^2

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3 years ago
Plz help <br> will mark brainliest for the correct answer
Harlamova29_29 [7]
Ethans is the correct one

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3 years ago
Tania is going to make soup. She combines 225 grams of water with 300 grams of condensed soup. Tania then adds 50 grams of celer
77julia77 [94]

Answer:

375 grams of soup sir I hope this helps

6 0
2 years ago
Plot the x- and y-intercepts to graph the equation. <br> y = 1/3x − 1
Trava [24]
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3 years ago
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A sector with a radius of 8 cm has an area of 56pi cm2. What is the central angle measure of the sector in radians?
Maurinko [17]

Answer:

\frac{7\pi}{4}.

Step-by-step explanation:

Given information:

Radius of circle = 8 cm

Area of sector = 56\pi\text{ cm}^2

Formula for area of sector is

A=\dfrac{1}{2}\theta r^2

where, r is radius and \theta is central angle in radian.

Substitute A=56\pi and r=8 in the above formula.

56\pi=\dfrac{1}{2}\theta (8)^2

56\pi=\dfrac{64}{2}\theta

56\pi=32\theta

\dfrac{56\pi}{32}=\theta

\dfrac{7\pi}{4}=\theta

Therefore, the measure of the sector in radians is \frac{7\pi}{4}.

6 0
3 years ago
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