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lyudmila [28]
3 years ago
5

What equation would represent the graph of the parabola y = 3x^2 - 4x - 1

Mathematics
1 answer:
jekas [21]3 years ago
3 0

This is the equations of a parabola

y = 3x^2 - 4x - 1 graphed is a parabolic arc

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It’s about functions please help and show work.
r-ruslan [8.4K]

Answer:

f(-6) = -2

Step-by-step explanation:

plug in k value (-6)

f(-6) = -6/2 + 1

theres two ways to solve for this

one way:

convert the whole number 1 to an improper fraction

f(-6) = -6/2 + 2/2

combine like terms

f(-6) = -4/2

divide -4 by 2

f(-6) = -2

second way:

divide -6 by 2

f(-6) = -3 + 1

combine like terms

f(-6) = -2

either way you get the same answer

use whichever is easiest for you

3 0
3 years ago
Please help me asap!!!
Dafna11 [192]

you need help

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5 0
3 years ago
Read 2 more answers
(-7x∧5 + 14 - 2x) + (10x∧4 + 7x + 5x∧5)
Maslowich
-7x^5 + 5x^5 +10x^4 -2x + 7x + 14= -2x^5 +10x^4 +5x + 14

Your answer is -2x^5 +10x^4 +5x + 14
7 0
3 years ago
Tom crossed the finish line 3.8 seconds after Steve. Steve finished the race in 45.1 seconds. If t represents Tom's race time, w
icang [17]
B is the correct answer not totally sure tho hope this helps
4 0
3 years ago
Read 2 more answers
A line passes through the point (-6, 6) and (-6, 2). In two or more complete sentences, explain why it is not possible to write
Galina-37 [17]
Try writing it in point-slope form and you will see why you have a problem.

slope m is equal to (y2-y1)/(x2-x1):

m = (y2-y1)/(x2-x1) = (2-6)/(-6 - -6) = -4/0

The denominator has a zero, so it is undefined.

Since the point-slope form requires "m" to be defined, you can't write the equation of the line using point-slope form.


7 0
3 years ago
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