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ololo11 [35]
2 years ago
14

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I need the answer fast!!!!!

Mathematics
1 answer:
ExtremeBDS [4]2 years ago
3 0

Answer:

Step-by-step explanation:

(a) the cost for each person is not always the same

The predicted number for 70$ would be

10

(b) the train appears to go the same distance each minute.

The predicted distance travled for 10 mintues would be

30

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Answer: 7/24

Step-by-step explanation:

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3 years ago
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Determine the domain of 3x+2/x-4
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Need help on some math "pictures "
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Which statement is true about the angles?
liq [111]

Complete Question:

Triangle abc has the angle mesausres shown.

m<A = (2x)°

m<B = (5x)°

m<C = (11x)°

Which statement is true about the angles?

A. m<A = 20°

B. m<B = 60°

C. m<A and m<B are complementary

D. m<A + m<C = 120°

Answer:

A. m<A = 20°

Step-by-step explanation:

m<A + m<B + m<C = 180° (sum of interior angles of a triangle)

2x + 5x + 11x = 180 (substitution)

Solve for x. Add like terms.

18x = 180

Divide both sides by 18

\frac{18x}{18} = \frac{180}{18}

x = 10

Find the measure of each angle by substituting x = 10:

m<A = (2x)° = 2(10) = 20°

m<B = (5x)° = 5(10) = 50°

m<C = (11x)° = 11(10) = 110°

Therefore, the only true statement is:

A. m<A = 20°

3 0
3 years ago
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The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian
Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }

Then the area of isosceles right triangle will be: A=\frac{1}{2} x^2

Therefore the area is: A=\frac{169}{4}

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

S=\frac{a}{1-r}

Substitute a=\frac{169}{4} \ and\ r=\frac{1}{4} in above formula.

S=\frac{\frac{169}{4}}{1-\frac{1}{4}}

S=\frac{\frac{169}{4}}{\frac{3}{4}}

S=\frac{169}{3}

Hence, the Sum of the areas of theses triangles is 169/3.

7 0
3 years ago
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