Answer:
The question is not complete, below is the completed question:
These triangles are scaled copies of each other. Four right triangles labeled F, B, G, and H. Triangle F has the vertical side labeled 8, the horizontal side labeled 6, and the longest side labeled 10. Triangle B has the vertical side labeled 2, the horizontal side labeled 3 halves, and the longest side labeled 5 halves. Triangle G has the vertical side labeled 4, the horizontal side labeled 3, and the longest side labeled 5. Triangle H has the vertical side labeled 8 thirds, the horizontal side labeled 2, and the longest side labeled 10 thirds. For each pair of triangles listed, the area of the second triangle is how many times larger than the area of the first? Remember that area is scale factor x scale factor.
1. Triangle G and Triangle F
2. Triangle G and Triangle B
3. Triangle B and Triangle F
4. Triangle F and Triangle H
5. Triangle G and Triangle H
6. Triangle H and Triangle B
Answer:
1. Triangle G and Triangle F = 4 times
2. Triangle G and Triangle B = 0.2 times
3. Triangle B and Triangle F = 16 times
4. Triangle F and Triangle H = 0.11 times
5. Triangle G and Triangle H = 0.44 times
6. Triangle H and Triangle B = 0.56 times
Step-by-step explanation:
using the image of the triangles attached to this solution, let us calculate the area of each pair of triangles
1. Area of Triangle = ![\frac{base\ \times\ height}{2}](https://tex.z-dn.net/?f=%5Cfrac%7Bbase%5C%20%5Ctimes%5C%20height%7D%7B2%7D)
![F = \frac{6 \times 8}{2} = \frac{48}{2} = 24\\B = \frac{\frac{3}{2} \times 2 }{2} = \frac{3}{2} = \frac{3}{2}\\ G = \frac{3 \times4}{2}= \frac{12}{2} = 6\\ H = \frac{2 \times \frac{8}{3} }{2} = \frac{16}{6} = \frac{8}{3}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B6%20%5Ctimes%208%7D%7B2%7D%20%3D%20%5Cfrac%7B48%7D%7B2%7D%20%3D%2024%5C%5CB%20%3D%20%5Cfrac%7B%5Cfrac%7B3%7D%7B2%7D%20%5Ctimes%202%20%7D%7B2%7D%20%3D%20%5Cfrac%7B3%7D%7B2%7D%20%20%3D%20%5Cfrac%7B3%7D%7B2%7D%5C%5C%20G%20%3D%20%5Cfrac%7B3%20%5Ctimes4%7D%7B2%7D%3D%20%5Cfrac%7B12%7D%7B2%7D%20%3D%206%5C%5C%20H%20%3D%20%5Cfrac%7B2%20%5Ctimes%20%5Cfrac%7B8%7D%7B3%7D%20%7D%7B2%7D%20%3D%20%5Cfrac%7B16%7D%7B6%7D%20%3D%20%5Cfrac%7B8%7D%7B3%7D)
To find by how many times the second triangle is larger than the first, we will calculate the ratio of the areas of the second triangle to the first
1. Triangle G and Triangle F = 24:6 = 4
∴ The area of triangle F is 4 times larger than triangle G
2. Triangle G and Triangle B = 3/2 : 6 =
= 0.2
∴ The area of triangle B is 0.2 times larger than triangle G
3. Triangle B and Triangle F = ![24 : \frac{3}{2} = 16](https://tex.z-dn.net/?f=24%20%3A%20%5Cfrac%7B3%7D%7B2%7D%20%3D%2016)
∴ The area of triangle F is 16 times larger than triangle B
4. Triangle F and Triangle H =
∴ The area of triangle H is 0.11 times larger than triangle F
5. Triangle G and Triangle H = ![\frac{8}{3} : 6 = \frac{4}{9} = 0.44](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B3%7D%20%3A%206%20%3D%20%5Cfrac%7B4%7D%7B9%7D%20%3D%200.44)
∴ The area of triangle H is 0.44 times larger than triangle G
6. Triangle H and Triangle B = ![\frac{3}{2} : \frac{8}{3} = \frac{9}{16} = 0.56](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7D%20%3A%20%5Cfrac%7B8%7D%7B3%7D%20%3D%20%5Cfrac%7B9%7D%7B16%7D%20%3D%200.56)
∴ The area of triangle B is 0.56 times larger than triangle H