Question

The following probability distributions of job satisfaction scores for a sample of information

Answer 1

Answer:

a. 4.05 b. 3.84 c. 1.2475 and 1.1344 d. 1.1169 and 1.0651  e. We can say that the overall job satistaction of senior executives and middle managers is about 4; however, there is more variability in the job satisfaction for senior executives than in the job satisfaction for middle managers.

Step-by-step explanation:

a. (1)(0.05)+(2)(0.09)+(3)(0.03)+(4)(0.42)+(5)(0.41) = 4.05

b. (1)(0.04)+(2)(0.1)+(3)(0.12)+(4)(0.46)+(5)(0.28) = 3.84

c. We compute the variances as follow: $[(1)^2(0.05)+(2)^2(0.09)+(3)^2(0.03)+(4)^2(0.42)+(5)^2(0.41)] - 4.05^2$ = 1.2475 and $[(1)^2(0.04)+(2)^2(0.1)+(3)^2(0.12)+(4)^2(0.46)+(5)^2(0.28)]-3.84^2$ = 1.1344

d. The standard deviation is the squared root of the variance, therefore, we have $\sqrt{1.2475} = 1.1169$ and $\sqrt{1.1344} = 1.0651$

e. The expected value of the job satisfaction score for senior executives is very similar to the job satisfaction score for middle managers. We can say that the overall job satistaction of senior executives and middle managers is about 4; however, there is more variability in the job satisfaction for senior executives than in the job satisfaction for middle managers.