Question

Solve the equation 58 - 10x ≤ 20 + 9x

Answer 1

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

$58-10x\leq20+9x$

Then, add $10x$ to both sides:

$58-10x+10x\leq20+9x+10x\\58\leq20+19x$

Next, subtract $20$ from both sides:

$58-20\leq20-20+19x\\38\leq19x$

Finally, divide both sides by $19$:

$\frac{38}{19}\leq\frac{19x}{19}\\2\leq x$

or

$x\geq 2$

Therefore: the answer to this inequality/equation is: x≥2