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ELEN [110]
3 years ago
13

Solve the equation 58 - 10x ≤ 20 + 9x

Mathematics
1 answer:
drek231 [11]3 years ago
6 0

Answer:

x≥2

Step-by-step explanation:

First, write out the equation as you have it:

58-10x\leq20+9x

Then, add 10x to both sides:

58-10x+10x\leq20+9x+10x\\58\leq20+19x

Next, subtract 20 from both sides:

58-20\leq20-20+19x\\38\leq19x

Finally, divide both sides by 19:

\frac{38}{19}\leq\frac{19x}{19}\\2\leq x

or

x\geq 2

Therefore: the answer to this inequality/equation is: x≥2

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