Answer:
The cost of the pillar is $22,947.12
Step-by-step explanation:
Diameter of the pillar = 6m
Radius = diameter / 2 = 6 / 2 = 3m
Height if the pillar = 7m
Volume of the pillar = πr²h
π = 3.14
V = 3.14 × 3² × 7
V = 3.14 × 9 × 7
V = 197.82m³
Volume of the pillar is 197.82m³
If 1m³ = $116
197.82m³ will cost $x
X = (197.82 × 116) / 1
X = $22,947.12
The cost of the pillar is $22,947.12
The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is 
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
Lets calculate areas:
single area = (78)(27) = 2106 ft^2
doubles area = (78)(27 + 9) = (78)(36) = 2808<span> ft^2</span>
junior area = (36)(18) = 648 ft^2
10&under area = (78 - 18)(27) = (60)(27) = 1620 <span>ft^2
</span>
The doubles area is bigger than the singles by 2808 - <span>2106 = 702 ft^2</span>
The singles area is bigger than the juniors by 2106 - 648 = 1458 <span>ft^2
</span>The singles area is bigger than the 10&under by 2106 - 1620 = 486 <span>ft^2</span>
