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svet-max [94.6K]
3 years ago
7

A tower is composed of a prism with a square base and

Mathematics
2 answers:
gregori [183]3 years ago
3 0

Answer:

a)400V2 plus 3,600 m2

Step-by-step explanation:

Svetllana [295]3 years ago
3 0

Answer:

400V2 + 3,600 m2

Step-by-step explanation:

Got it right on edge

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Solve.<br><br>10.8 - (-6.4) ×3​
Artist 52 [7]

Answer:

51.6

Step-by-step explanation:

10.8 - -6.4 is 17.2

17.2 x 3 is 51.6

4 0
3 years ago
Read 2 more answers
Can Anyone help please ?
anastassius [24]

Answer:

hey can you write it on the comments what it says so I can see it please and the equation

5 0
3 years ago
Glen Cove has a population of 7,200, which is decreasing at a
slamgirl [31]

Answer:

11 years

Step-by-step explanation:

7200  -  80x  =  5000  +  120x
-5000 + 80x    -5000 + 80x
           2200 = 200x
                  11 = x

4 0
2 years ago
What is the slope of the line?<br> 2x - 5y = 9<br> Choose 1 answers<br> 5<br> 2<br> O
Zepler [3.9K]

9514 1404 393

Answer:

  D.  2/5

Step-by-step explanation:

The slope is the x-coefficient when the equation is solved for y.

  2x -5y = 9 . . . . . . . given

  -5y = -2x +9 . . . . . .subtract 2x

  y = (-2/-5)x +9/(-5) . . . . divide by -5

  y = 2/5x -9/5

The coefficient of x is 2/5. That is the slope of the line.

The slope is 2/5.

5 0
3 years ago
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
4 years ago
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