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3 years ago

How do you solve this problem step by step

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

You start by adding 4 to both sides, isolating the X. then you have your answer X < 3

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If three out of four side lengths are all the same would that be a parallelogram?

grandymaker [24]

Answer:

Step-by-step explanation:

4 0

3 years ago

Barry wants to take out a loan from his bank for $1,000 to buy a bicycle. The interest rate on the loan from the bank is 9%. He

tekilochka [14]

Answer:

The amount that Barry would pay in interest for his loan is $15.05.

Step-by-step explanation:

To calculate this, we first calculate the monthly required fixed payment using the formula for calculating loan amortization as follows:

P = (A * (r * (1 + r)^n)) / (((1+r)^n) - 1) .................................... (1)

Where,

P = Monthly required fixed payment = ?

A = Loan amount = $1,000

r = monthly interest rate = 9% / 12 = 0.09 / 12 = 0.0075

n = number of payment months = 3

Substituting all the figures into equation (1), we have:

P = ($1,000 * (0.0075 * (1 + 0.0075)^3)) / (((1 + 0.0075)^3) - 1)

P = $338.35

Therefore, we have:

Total repayment = P * 3 months = $338.35 * 3 = $1,015.05

Interest amount = Total repayment - Loan principal = $1,015.05 - $1,000 = $15.05.

Therefore, the amount that Barry would pay in interest for his loan is $15.05.

3 0

2 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .