1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lunna [17]
3 years ago
10

Please help with this question!!

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

  -29/20

Step-by-step explanation:

The cosecant function is the inverse of the sine function. Both sine and cosecant are odd functions, meaning csc(-x) = -csc(x) = -1/sin(x).

  csc(-θ) = -1/sin(θ) = -1/(20/29) = -29/20

You might be interested in
20000 devided by 75
geniusboy [140]
20000 divided by 75 is 266.6666666667
7 0
3 years ago
Read 2 more answers
A sample is chosen randomly from a population that was strongly skewed to the left. a) Describe the sampling distribution model
Nana76 [90]

Answer:

a. The sampling distribution for the sample mean will be skewed to the left centered at the average u, and standard deviation will be  ∅/\sqrt{n}

b. The sample distribution will be normal in shape and will be centered at the average u, . standard deviation will be ∅/\sqrt{n}1

c. As the size of the sample increases, the sample distribution should draw near  and resemble the distribution of the population

Step-by-step explanation:

A sample is chosen randomly from a population that was strongly skewed to the left. a) Describe the sampling distribution model for the sample mean if the sample size is small. b) If we make the sample larger, what happens to the sampling distribution model’s shape, center, and spread? c) As we make the sample larger, what happens to the expected distribution of the data in the sample?

The following answers will march the questions above:

a. The sampling distribution for the sample mean will be skewed to the left centered at the average u, and standard deviation will be  ∅/\sqrt{n}

b. The sample distribution will be normal in shape and will be centered at the average u, . standard deviation will be ∅/\sqrt{n}1

c. As the size of the sample increases, the sample distribution should draw near  and resemble the distribution of the population

4 0
3 years ago
The LCD for the fractions 1/3, 3/4, 5/32, and 8/9 is
tekilochka [14]
288 is the LCD for this set of fractions
8 0
3 years ago
Divide 111001 by 1101​
omeli [17]

Step-by-step explanation:

100.81834696...is your answer

or 100.81

3 0
3 years ago
Wich of the following statements are true?​
alekssr [168]

Answer:

B and D

Step-by-step explanation:

A can't be correct because the length of a segment is always positive. B is correct because we have to take the absolute value of the distance between endpoints to find the length of the segment. C is not correct because AC is obviously longer than BC so how would AB + AC = BC? D is correct because it models the Parts Whole Postulate.

4 0
3 years ago
Other questions:
  • How do write a word problem for the following equation:
    15·1 answer
  • Point (k, -3) lies on the line whose equation is x-2y=-2. What is the value of k?
    15·1 answer
  • Which term describes a fraction that has a variable or variable expression in its numerator, its denominator, or both?
    14·2 answers
  • HELP??? Which expression is represented by the model?
    9·2 answers
  • How many planes appear in this figure? Name three points that are collinear. Are points a, b, c, and d coplanar? Explain. At wha
    7·1 answer
  • Line plot
    13·1 answer
  • Subtract (3x - 7x^2 + 2) - (4x^2 - 5 + 6x)
    12·1 answer
  • christina and her 2 friends spent $25.02 at there favorite restaraunt . if they split the cost equally how much will they each p
    12·1 answer
  • Which segment is a reflection of segment AB over the line x = 1?
    10·2 answers
  • A sociologist is doing a study on journalists. He attends a journalism conference, where he randomly surveys 390 journalists abo
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!