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Lunna [17]
3 years ago
10

Please help with this question!!

Mathematics
1 answer:
barxatty [35]3 years ago
6 0

Answer:

  -29/20

Step-by-step explanation:

The cosecant function is the inverse of the sine function. Both sine and cosecant are odd functions, meaning csc(-x) = -csc(x) = -1/sin(x).

  csc(-θ) = -1/sin(θ) = -1/(20/29) = -29/20

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Help i dont understand Pls help :(
olya-2409 [2.1K]

Answer:

x = 1?

Step-by-step explanation:

I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think

if f(x) = -5x + 1 when f(x) = 6,

replace f(x) with 6 so,

6 = 5x + 1

1 - 6 = 5x + 1 - 1

(subtract one on both sides to isolate the variable)

5 = 5x

5/5 = 5x/5

(to Actually isolate the variable lol

1 = x or x = 1

I believe is the answer? please comment if I'm wrong

*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD

5 0
3 years ago
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y)^6 are _____.
Kryger [21]
Using the triangle of pascal we have that the expression equivalent to (x + y) ^ 6 is given by:
 x ^ 6 + 6x ^ 5y + 15x ^ 4y ^ 2 + 20x ^ 3y ^ 3 + 15x ^ 2y ^ 4 + 6xy ^ 5 + y ^ 6
 Therefore, the coefficients of the expansion are given by:
 1, 6, 15, 20, 15, 6, 1
 Answer:
 
The coefficients corresponding to k = 0, 1, 2, ..., 6 in the expansion of (x + y) ^ 6 are 1, 6, 15, 20, 15, 6, 1
5 0
3 years ago
Read 2 more answers
Consider the following data set:
Komok [63]

Answer:

+5 Range; The range is now 25

Step-by-step explanation:

The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.

3 0
3 years ago
Suppose you choose a team of two people from a group of n > 1 people, and your opponent does the same (your choices are allow
jonny [76]

Answer:

The number of possible choices of my team and the opponents team is

 \left\begin{array}{ccc}n-1\\E\\n=1\end{array}\right     i^{3}

Step-by-step explanation:

selecting the first team from n people we have \left(\begin{array}{ccc}n\\1\\\end{array}\right)  = n possibility and choosing second team from the rest of n-1 people we have \left(\begin{array}{ccc}n-1\\1\\\end{array}\right) = n-1

As { A, B} = {B , A}

Therefore, the total possibility is \frac{n(n-1)}{2}

Since our choices are allowed to overlap, the second team is \frac{n(n-1)}{2}

Possibility of choosing both teams will be

\frac{n(n-1)}{2}  *  \frac{n(n-1)}{2}  \\\\= [\frac{n(n-1)}{2}] ^{2}

We now have the formula

1³ + 2³ + ........... + n³ =[\frac{n(n+1)}{2}] ^{2}

1³ + 2³ + ............ + (n-1)³ = [x^{2} \frac{n(n-1)}{2}] ^{2}

=\left[\begin{array}{ccc}n-1\\E\\i=1\end{array}\right] =   [\frac{n(n-1)}{2}]^{3}

4 0
3 years ago
Write an equation for the following problem and then solve the equation.
melomori [17]

Answer:bhbehrf

Step-by-step explanation:

7 0
3 years ago
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