Set equal to each other
x^2 - 8 = 2x
x^2 - 2x - 8 = 0
Factor
(x - 4)(x + 2) = 0
x = 4 or x = -2
Plug in 4
y = 2x or y = x^2 - 8
y = 2(4) or y = 4^2 - 8
y = 8
Plug in -2
y = 2x or y = x^2 - 8
y = 2(-2) or y = (-2)^2 - 8
y = -4
There are two solutions
(4, 8) and (-2, -4)
Answer:
{0,6}
Step-by-step explanation:
You need to find all x that belong to A but do not belong to B.
0, 6 are the only ones.
Hope it helps and if it does, plzzzz mark me BRAINLIEST!!!
Answer:
Step-by-step explanation:
Answer:
$6250
Step-by-step explanation:
if im correct plz can i get a brainliest
Answer:
The new point would be (-3,-6)
Step-by-step explanation:
To solve this it is nice to graph the first point at (1,-1). Then move the point left 4 units, making x -3. and then 5 units down, which would make y -6.
