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3 years ago

PQR and PSR are inscribed in circle A. What is mQPR?

Mathematics

1 answer:

Lera25 [3.4K]3 years ago

6 0

The answer is mQPR=42... i looked it up

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If BE=9cm, find GE What is the answer

Sladkaya [172]

Answer:

GE = 3 cm

Step-by-step explanation:

BE = 9 cm

Since G is the centroid, therefore:

$GE = \frac{1}{3}(BE)$ => Centroid theorem

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$GE = \frac{1}{3}(9)$

GE = 3 cm

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3 years ago

Triangle ABC is formed by the vertices A(1,2,-1), B(-3,-6,2)and C(3,-2,0).

Vesnalui [34]

Answer:

Point D: $(0,-4, 1 )$

d = √41

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Pre-Calculus

Midpoint Formula [3D]: $(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}, \frac{z_1+z_2}{2} )$
Distance Formula [3D]: $d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Step-by-step explanation:

Step 1: Define

Point A(1, 2, -1)

Point B(-3, -6, 2)

Point C(3, -2, 0)

Step 2: Find Point D

Simply plug in your coordinates B and C into the midpoint formula to find midpoint

Substitute [MF]: $(\frac{-3+3}{2},\frac{-6-2}{2}, \frac{2+0}{2} )$
Add/Subtract: $(\frac{0}{2},\frac{-8}{2}, \frac{2}{2} )$
Divide: $(0,-4, 1 )$

Step 3: Find distance d

Simply plug in the 2 coordinates A and D into the distance formula to find distance d

Substitute [DF]: $d = \sqrt{(0-1)^2+(-4-2)^2+(1+1)^2}$
Subtract/Add: $d = \sqrt{(-1)^2+(-6)^2+(2)^2}$
Exponents: $d = \sqrt{1+36+4}$
Add: $d = \sqrt{41}$

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3 years ago