A tree that grows 3 feet every 5 years is growing at a rate of ___ feet per year. A.0.6 B.15 C.60

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

8 0

Answer:

The correct option is A. 0.6

Step-by-step explanation:

Given,

Growth of the tree in 5 years = 3 feet,

So, the growth in 1 year = $\frac{1}{5}$ × Growth of the tree in 5 years

$=\frac{1}{5}\times 3$

$=0.6\text{ feet}$

Hence, the rate of growing the tree is 0.6 feet per year.

i.e. OPTION A is correct.

sammy [17]2 years ago

7 0

A.0.6
0.6*5yrs=3feet a year

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bonufazy [111]

Answer:

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Step-by-step explanation:

$7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)$

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factors of 2: 2

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factors of 8: 2x2x2

Putting these values in our equation: $=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)$

Adding like terms we get:

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