N-acetyltyrosine ethyl ester may likely have a higher Vmax.
<h3>How are the Km and Vmax of an enzyme and substrate related?</h3>
Km is inversely proportional enzyme affinity for substrate. The lower the Km, the higher the enzyme affinity for substrate and vice versa.
Vmax is the maximum velocity of the reaction when the enzyme is fully saturated with substrate.
Based on the Km values, chymotrypsin has higher affinity for N-acetyltyrosine ethyl ester, thus, N-acetyltyrosine ethyl ester may likely have a higher Vmax.
In conclusion, the Vmax is the maximum velocity of an enzyme-catalyzed reaction.
<em>Note that the complete question is given below:</em>
<em>The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M.</em>
<em>Which of the following substrates is likely to give a higher value for Vmax?</em>
Learn more about Km and Vmax at: brainly.com/question/16108691
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The problem express that the fraction of time
worked by the three people need to be equivalent to one person working full
time. This means that the fraction need to add up to one. We know one person
works ½ time on the project and another works one third 1/3 time.
Given:
A = the amount of time that the third person needs
to work on the job to add up to one
1 = ½ +1/3 + A
1 – ½ - 1/3 = A
To subtract the fractions put them all over a
common denominator. Use 3 * 2 as the denominator.
1=6/6, ½ = 3/6, 1/3 = 2/6
A = 6/6 – 3/6 – 2/6
<span>A = 1/6 , The third person must work on the project</span>
-1/2ac^2 flip to make it positive which makes it a whole number = 2ac^2
Answer:
V = 64 and V = 2,048
Step-by-step explanation:
The volume of a cube is found using V = s*s*s. Substitute s = 4.
The volume is V = 4*4*4 = 64.
The volume of the crate is 32 * 64 = 2,048.
Is the answer 240.is that one of your options
