If A and B are equal:
Matrix A must be a diagonal matrix: FALSE.
We only know that A and B are equal, so they can both be non-diagonal matrices. Here's a counterexample:
![A=B=\left[\begin{array}{cc}1&2\\4&5\\7&8\end{array}\right]](https://tex.z-dn.net/?f=A%3DB%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%262%5C%5C4%265%5C%5C7%268%5Cend%7Barray%7D%5Cright%5D)
Both matrices must be square: FALSE.
We only know that A and B are equal, so they can both be non-square matrices. The previous counterexample still works
Both matrices must be the same size: TRUE
If A and B are equal, they are literally the same matrix. So, in particular, they also share the size.
For any value of i, j; aij = bij: TRUE
Assuming that there was a small typo in the question, this is also true: two matrices are equal if the correspondent entries are the same.
Answer:
The answer is 5.
Step-by-step explanation:
17 / 4 + 3 / 4 =
(17 × 4) + (3 × 4)
4 × 4 = 80 / 16 =
80 ÷ 16
16 ÷ 16
= 5
Hope this helps!
Yes I love this problem so good
Answer:
They give you the answer just keep going until you get the same answer or use the inverse of what they did
Step-by-step explanation:
Answer:
x=90º
Step-by-step explanation:
x=60+30
x=90