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Amiraneli [1.4K]
3 years ago
9

Which fraction is equivalent to StartFraction 5 Over 20 EndFraction? StartFraction 4 Over 16 EndFraction, because StartFraction

5 Over 20 EndFraction = one-fourth and One-fourth = StartFraction 4 Over 16 EndFraction StartFraction 4 Over 12 EndFraction, because StartFraction 5 Over 20 EndFraction = one-fourth and One-fourth = StartFraction 4 Over 12 EndFraction StartFraction 4 Over 19 EndFraction, because StartFraction 5 Over 20 EndFraction = StartFraction 5 minus 1 Over 20 minus 1 EndFraction = StartFraction 4 Over 19 EndFraction StartFraction 4 Over 15 EndFraction, because StartFraction 5 Over 20 EndFraction = one-fifth = StartFraction 5 minus 1 Over 20 minus 5 EndFraction = StartFraction 4 Over 15 EndFraction
Mathematics
2 answers:
den301095 [7]3 years ago
7 0

Answer:

a

Step-by-step explanation:

fredd [130]3 years ago
6 0

Answer:

\frac{5}{20} = \frac{1}{4} = \frac{4}{16}

Step-by-step explanation:

Given

Fraction = \frac{5}{20}

Required

Get equivalent fractions

Fraction = \frac{5}{20}

Divide numerator and denominator by 5

Fraction = \frac{5/5}{20/5}

Fraction = \frac{1}{4}

Multiply the numerator ad denominator by 4

Fraction = \frac{1 * 4}{4 * 4}

Fraction = \frac{4}{16}

Hence:

\frac{5}{20} = \frac{1}{4} = \frac{4}{16}

<em>Option A answers the question</em>

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Find three consecutive integers such as two times the first integer, plus three times the second integer, minus the third intege
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The three consecutive integers are 5, 6, and 7.

What are consecutive integers?

Whole numbers that follow one another without a gap are known as consecutive integers. A few examples of consecutive integers are 15, 16, and 17, 1,2 and 3, and so on.

Finding the Consecutive Integers

Let the three consecutive integers be a, a + 1, and a + 2.

These three consecutive integers are to be such that two times the first integer when added to three times the second integer minus the third integer, it is equal to 21.

⇒ 2a + 3(a+1) - (a+2) = 21

2a + 3a + 3 - a -2 = 21

5a - a + 3 - 2 = 21

4a + 1 = 21

4a = 20

a = 20/4

a = 5

∴ a+1 = 5+1

a+1 = 6

And, a+2 = 5 + 2

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Hence, the three consecutive integers come out to be 5, 6, and 7

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3 years ago
Given the piece wise function show below, select all that are true​
NeTakaya

Answer:

Option (C) and (D)

Step-by-step explanation:

Given piecewise function is,

f(x) = 2x, x < 1

        5, x = 1

        x^{2}, x > 1

Option (A),

x = 5 means x > 1

So the function will be,

f(x) = x^{2}

f(5) = (5)²

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Therefore, f(5) = 1 is not correct.

Option (B),

x = -2 means x < 1

f(x) = 2x will be applicable.

f(-2) = 2(-2) = -4

Therefore, f(-2) = 4 is not correct.

Option (C)

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Therefore, f(1) = 5 is the correct option.

Option (D)

x = 2 means x > 1 and the function defined will be,

f(x) = x²

f(2) = 2²

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Therefore, f(2) = 4 will be the correct option.

Options (C) and (D) will be the answer.

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