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Mila [183]
3 years ago
11

In △BCD, BP=15 cm. What the length of BX¯¯¯¯¯¯ ? Enter your answer in the box. __cm

Mathematics
1 answer:
rodikova [14]3 years ago
4 0
It should be 10 cm  but if its wrong plz tell me
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Three apples and two oranges cost $3.80, while two apples and one orange costs $2.30 Find the cost of an orange.
zaharov [31]
The cost of an orange would be $6.10
5 0
3 years ago
27.9km to the nearest km
yuradex [85]

Answer: It rounds to <u>28 km</u>

Explanation:

The units or ones digit is "7". The next digit over (9) is five or larger. This means we bump the 27 up to 28. Everything after the 7 is ignored.

So we could have something like 27.999871212512 and we still follow the same idea of focusing on the 27, bumping it up to 28, and everything else gets ignored.

The reason for this is because 27.9 is much closer to 28 than it is to 27. Draw out a number line to help see this. Split the region from 27 to 28 into 10 equal pieces. The 9th little piece represents 27 & 9/10 aka 27.9

Refer to the number line diagram below.

8 0
2 years ago
A truck weighs 5400 lb in Open Wheel race car weighs 1/4 as much how much does the race car weigh
kap26 [50]
1,350 pounds

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4 0
3 years ago
Read 2 more answers
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
If f (x) = StartRoot one-half x minus 10 EndRoot + 3, which inequality can be used to find the domain of f(x)?
just olya [345]

The inequality that represents the domain of the function is \frac 12x - 10 \ge 0

<h3>How to determine the domain?</h3>

The function is given as:

f(x) = \sqrt{\frac 12x - 10} + 3

Set the radicand greater than or equal to 0

\frac 12x - 10 \ge 0

Multiply through by 2

x - 20 ≥ 0

Add 20 to both sides

x ≥ 20  

Hence, the domain of the function is x ≥ 20  

Read more about domain at:

brainly.com/question/1770447

#SPJ1

7 0
2 years ago
Read 2 more answers
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