2 years ago

Svp je veux une aide avec la question n°2 de l'exercice n°3

Mathematics

1 answer:

Akimi4 [234]2 years ago

4 0

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The mean weight 20 students in a room is 65 kg one student one student who weight is 88kg went into the room what is the new mea

umka2103 [35]

The new mean is 66.09

<u>Explanation:</u>

Mean weight of 20 students = 65kg

One student with 88kg entered the room.

New mean = ?

$\frac{x_1+x_2+....+x_2_0}{20} = 65$

$\frac{x_1+x_2+....+x_2_0 + 88}{21} = ?$

The above equation can further be written as:

$x_1 + x_2 +....+x_2_0 = 65 X 20\\\\x_1 + x_2 +....+x_2_0 = 1300$

New mean = $\frac{1300 + 88}{21}$

= 66.09

Therefore, the new mean is 66.09

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3 years ago

Solve for the value of c.

Ipatiy [6.2K]

Answer:

2c-4+5c+3 = 90

7c-1 = 90

7c = 91

c = 13

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2 years ago

PLEASE HELP THIS IS URGENT!!!<br> what is 2+2

lisov135 [29]

Answer:

Step-by-step explanation:

Hope this helps!! Have a good day!

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2 years ago

What is the solution to 3/4b=8

soldier1979 [14.2K]

Answer:

$b=\frac{32}{3}$

Step-by-step explanation:

$\frac{3}{4}b=8$

Multiply both sides by 4:

$4\times \frac{3}{4}b=8\times4$

$3b=32$

Divide both sides by 3:

$\frac{3b}{3}=\frac{32}{3}$

$b=\frac{32}{3}$

6 0

3 years ago

First to answer gets brainliest

Grace [21]

Answer: 14
Square both sides, getting you
2x-3=25
Add 3 to both sides
2x=28
Divide both sides by 2
x=14

8 0

3 years ago

Read 2 more answers