Answer:
K = (1/2)r^2(sin(θ) +θ)
Step-by-step explanation:
The area of the triangle to the left is ...
A1 = (1/2)r^2·sin(180°-θ) = (1/2)r^2·sin(θ)
The area of the sector to the right is ...
A2 = (1/2)r^2θ
so the total area of the blue shaded region is ...
K = A1 + A2 = (1/2)r^2·sin(θ) + (1/2)r^2·θ
K = (1/2)r^2(sin(θ) +θ)
<h2>1)</h2>
This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.
<h2>2)</h2>
Well he started off correct to the point of completing the square.
20% of 36.69 is 7.338
36.69 + 7.338 = 44.02800 divided by 4 = $11.007 (rounded)
Each friend paid $11.01
Hello,
1. Since Angle C has the longest side for this triangle, it will have the largest degree value.
2. Use the Law of Cosines and inverse properties of “theta” to solve for Angle C. (Ensure that the calculator used is in “degree mode”, not “radian mode”.
c^2 = a^2 + b^2 - 2(a)(b)(cos (C))
15^2 = 11^2 + 14^2 - 2(11)(14)(cos(C))
225 - 317 = -2(11)(14)(cos(C))
-92 / -2(11)(14) = cos(C)
cos(C) becomes ->> cos^-1[92 /-2(11)(14)] = 72.62° ->> to the nearest degree is 73°
The answer for angle C, 73°, is logical because the triangle in the picture represents a 60-60-60 triangle, known as an equilateral triangle.
Good luck to you!
Yes, it is.
(31√5) / √65=31√(5/65)
Answer: yes, it is.
