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Alexxx [7]
3 years ago
15

Please answer this correctly for a Brainliest

Mathematics
1 answer:
aksik [14]3 years ago
8 0
The answer is 252 square feet
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Hi i just wanna know if i'm right on this math question<br><br> Thank you.
Stolb23 [73]

Answer:

Correct my guy or gal.

Step-by-step explanation:

6 0
3 years ago
Find the volume of a cylinder with a radius of 5 cm and a height of 10 cm. Then, find the volume of the cylinder if the radius i
kap26 [50]

Answer:

250π

1000π

Step-by-step explanation:

(refer to attached)

volume of cylinder is given by:

V = π r²h,

where r = radius of base and h = height of cylinder

Given r = 5 and h = 10, hence

V = π r²h

V = π (5)²(10)

V = π (25) (10)

V = 250π  (answer)

For the second case, r = 10 cm

V = π r²h

V = π (10)²(10)

V = π (100) (10)

V = 1000π  (answer)

3 0
3 years ago
Read 2 more answers
Suppose that you take 1000 simple random samples from a population and that, for each sample, you obtain a 95% confidence interv
Bogdan [553]

Using the interpretation of a confidence interval, it is found that approximately 950 of those confidence intervals will contain the value of the unknown parameter.

A x% confidence interval means that we are x% confident that the population mean is in the interval.

  • Out of a large number of intervals, approximately x% will contain the value of the unknown parameter.

In this problem:

  • 95% confidence interval.
  • 1000 samples.

0.95 x 1000 = 950

Hence, approximately 950 of those confidence intervals will contain the value of the unknown parameter.

A similar problem is given at brainly.com/question/24303674

3 0
3 years ago
Find the percent of each number 0.9 of 1000
trasher [3.6K]

We can use the is/of = p/100 method here. Our given values are 90% and 1000. Think: "What number is 90% of 1000?" Let's plug in our values.

x/1000 = 90/100

Solve for x.

x = (1000)(0.9)

x = 900

So, 900 is 90% of 1000.

8 0
3 years ago
-12 = 6+ 2/3 y<br><br><br> Pleaseeeee help me ❤️
jek_recluse [69]
The answer is Y=-27 hope it helps
4 0
3 years ago
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