The factors of the given expression are x , x - 2 and x - 4
![V(x)= x^{3}- 6x^{2}+8x \\ \\ V(x)=x( x^{2} -6x+8) \\ \\ V(x)=x( x^{2} -2x-4x+8) \\ \\ V(x)=x[x(x-2)-4(x-2)] \\ \\ V(x)=x(x-2)(x-4)](https://tex.z-dn.net/?f=V%28x%29%3D%20x%5E%7B3%7D-%20%206x%5E%7B2%7D%2B8x%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-6x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28%20x%5E%7B2%7D%20-2x-4x%2B8%29%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%5Bx%28x-2%29-4%28x-2%29%5D%20%5C%5C%20%20%5C%5C%20%0AV%28x%29%3Dx%28x-2%29%28x-4%29%20)
So the expression for height and length are x and x - 4
So the expression for height and length are x and x - 4
Which recursive formula can be used to generate the sequence shown, where f(1) = 5 and n > 1? 5,–1, –7, –13, –19, ...
1 answer:
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9514 1404 393
Answer:
see attached
Step-by-step explanation:
The scale of the drawing is 50 m per grid square.
The magnitude of the resultant can be found using the Pythagorean theorem:
r = √(n² +e²)
r = √(500² +200²) = 100√29 ≈ 538.52 . . . meters
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The direction angle can be found using the arctangent function.
The angle east of north is ...
arctan(200/500) ≈ 21.8014°
The resultant is 538.52 meters in the direction 21.8° east of north.
