Y = -10 and x = -13 (substitute 2y + 7 for x)
The given plane,
, has normal vector
. Any plane parallel to this one has the same normal vector.
Let
be any point in the plane we want. The plane contains the point (1, 1, -1), so an arbitrary vector in this plane is

and this is perpendicular to
.
So the equation of the plane is

or equivalently,

Answer:
A:1.1 I had the same answer
D) the x intercept as you let each bracket equal to 0 to find the x coordinate
I think The last one in right
y |2| 6 |10 |14
x |6 |18 |30 |42