Find BC. Round the answer to the nearest tenth. A. 1.1 B. 1.9 C. 2.3 D. 2.8

How can the figure below be changed so that it has exactly one lines of symmetry?

frez [133]

Answer:

C

Step-by-step explanation:

By moving point B 1.5 units to the right, you create an icoselles triangle, which has just one line of symmetry

4 0

3 years ago

A shipping container holds 20 soft drink boxes. The dimensions of a soda box are 15 inches by 4 inches by 5 inches. What is the

patriot [66]

Answer:

6000 in³

Step-by-step explanation:

To solve this problem, we simply have to find the volume of the shipping container that will be just enough to contain the 20 soda boxes.

To do this, we find the volume of each soda box and multiply it by the total number of soda boxes held by the shipping container.

Volume of the box = L * B * H

L = length = 15 in

B = breadth = 4 in

H = height = 5 in

V = 15 * 4 * 5 = 300 in³

This is the volume of each soda box.

The volume of 20 soda boxes will then be:

V = 20 * 300 = 6000 in³

This is the volume of 20 soda boxes and hence, the minimum size the shipping container can be.

7 0

3 years ago

A promoter buys advertising in units of $30,000 each. If he buys two units of broadcast TV, one unit of cable TV, and two units

andriy [413]

Answer:

$150,000

Step-by-step explanation:

The first step is to calculate the total number of units

= 2 +1 +2

= 5

If he buys at the rate of $30,000 for one unit then the total money spent on advertising can be calculated as follows

= 30,000 × 5

= 150,000

Hence the promoter spends $150,000 on advertising

4 0

3 years ago

Help me with Thai math it’s worth 22 points PLZZ answer ALL of them

joja [24]

Answer:

supply (B)
A step in process (A)
(b)
(A)

5 0

2 years ago

B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing

kenny6666 [7]

Answer:

$\boxed{ \boxed{ \sf {Marked \: price \: = Rs \: 1500}}}$

$\boxed{ \bold{ \boxed{ \sf{Selling \: price = \: Rs \: 1230}}}}$

Step-by-step explanation:

Let Cost price ( C.P ) be x

Finding the Marked price and selling price 

Marked price = $\sf{x + 20\% \: of \: x}$

⇒ $\sf{x + \frac{20}{100} \times x}$

⇒ $\sf{ \frac{x \times 100 + 20x}{100} }$

⇒ $\sf{ \frac{120x}{100} }$ ⇒ ( i )

Selling price = $\sf{marked \: price \: - 18\% \: of \: marked \: price}$

⇒ $\sf{ \frac{120x}{100} - \frac{18}{100} \times \frac{120x}{100} }$

⇒ $\sf{ \frac{120x}{100} - \frac{54x}{250} }$

⇒ $\sf{ \frac{120x \times 5 - 54x \times 2}{500} }$

⇒ $\sf{ \frac{600x - 108x}{500} }$

⇒ $\sf{ \frac{492x}{500} }$ ⇒ ( ii )

Finding the value of x ( Cost price )

$\sf{loss = cost \: price - selling \: price}$

⇒ $\sf{20 = x - \frac{492x}{500} }$

⇒ $\sf{20 = \frac{x \times 500 - 492x}{500} }$

⇒ $\sf{20 = \frac{8x}{500} }$

⇒ $\sf{8x = 10000}$

⇒ $\sf{x = \frac{10000}{8} }$

⇒ $\sf{x = \: Rs \: 1250}$

Value of x ( cost price ) = Rs 1250

Now, Replacing the value of x in ( i ) in order to find the value of marked price

$\sf{marked \: price = \frac{120x}{100} }$

⇒ $\sf{ \frac{120 \times 1250}{100} }$

⇒ $\sf{ \: Rs \: 1500}$

Replacing value of x in ( ii ) in order to find the value of selling price

$\sf{selling \: price = \frac{492 \: x}{500} }$

⇒ $\sf{ \frac{615000}{500} }$

⇒ $\sf{ \: Rs \: 1230}$

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0

3 years ago